To solve this problem you must follow the proccedure shown below:
1. You have that <span>the pasture must contain 128 square meters and no fencing is required along the river. Then:
A=LxW
A is the area
L is the lenght
W is the width
2. Let's clear W:
W=A/L
W=128/L
3. The formula of the perimeter is:
P=2L+W
P=2L+(128/L)
4. Now, you must derivate:
dP/dL=0
2+(128/L</span>²)=0
<span> L=8 meters
W=A/L
W=128/8
W=16 meters
</span>
There are 24 oranges and 36 apples.
Each basket has to have the same number of fruit
So lets say that each basket will have exactly one orange and apple.
To get the maximum number of baskets, we have to use either all of the apples or all of the oranges.
You can't have 36 baskets, because you only have 24 oranges, even though there are enough apples.
But you can 24 baskets, because there are enough apples and oranges.
So you can use all of the oranges to make 24 baskets (and you'll be left with 12 apples)
Answer: F. 24.
Answer:
$91. 91
Step-by-step explanation:
i used a tip and tax calculator :))) hope this helps
Answer:
Step-by-step explanation:
y= a*b x (a is initial value b = growth rate) y= 8000(-1)^1 x= 1.018^1 x 1.8
x = 0.1527 = time x 12.
f(x)=x. f ( x ) = x . = 0.1527 x 12
or we can square so that x^2 = 1.8 and x = 1.34164 note this can only be used for the first 5 decimal place.
This shows the exponential growth we expand and introduce y = 8000(-1)^12 to find one year.
One year y-1^12 this represents 144 the 1.8% of the y = 144 the starting point of 1/12 on axis.
f(x)=2x. f ( x ) = 2x add y (1)^1 would show year 2 at the same rate,
Answer:
Range = 2460 dollars, Variance = 516414.6 
, Standard deviation = 718.6199 dollars . There are two outliers and they are likely to have much of an effect on the measures of variation.
Step-by-step explanation:
The smallest value in the sample data is min = 50 dollars and the largest value is max = 2500 dollars, therefore, the range is Range = max - min = 2500 - 40 = 2460 dollars. On the other hand, the formula to compute the sample variance is 
where 
is the sample mean, n is the sample size and the 
are the sample values. In this case the sample variance is 
= 516414.6 , the sample standard deviation is defined as the squared root of the sample variance, so, the sample standard deviation is s = 718.6199 dollars. There are two outliers because 1750 dollars and 2500 dollars are very different compared to the other values, these two numbers are very large and they are likely to have much of an effect on the measures of variation because these measures are sensible to outliers, they are no robust measures.
