Please help, much needed. A lot of points

Mathematics

2 answers:

svetoff [14.1K]2 years ago

8 0

Answer:

A. -9

Step-by-step explanation:

If one of the variables were negative than, it would not be able to equal 2/7.

Ivanshal [37]2 years ago

6 0

It’s A which is -9, have a good day

You might be interested in

One jar of crushed ginger costs $1.99. How many jars can you buy for $17.91?

dangina [55]

Answer:

Step-by-step explanation:

17.91 divided by 1.99

8 0

2 years ago

Read 2 more answers

Look at the graph below.

romanna [79]

Where is the graph? Because it would be a lot easier to answer this if you could show a picture of the graph

8 0

3 years ago

Read 2 more answers

1 pt) If a parametric surface given by r1(u,v)=f(u,v)i+g(u,v)j+h(u,v)k and −4≤u≤4,−4≤v≤4, has surface area equal to 1, what is t

natta225 [31]

The area of the surface given by $\vec r_1(u,v)$ is 1. In terms of a surface integral, we have

$1=\displaystyle\int_{-4}^4\int_{-4}^4\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

By multiplying each component in $\vec r_1$ by 5, we have

$\dfrac{\partial\vec r_2(u,v)}{\partial u}=5\dfrac{\partial\vec r_1(u,v)}{\partial u}$

and the same goes for the derivative with respect to $v$ . Then the area of the surface given by $\vec r_2(u,v)$ is

$\displaystyle\int_{-4}^4\int_{-4}^425\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\boxed{25}$