Subtract
6
6
from both sides of the equation.
x
2
−
7
x
=
−
6
x
2
-
7
x
=
-
6
To create a trinomial square on the left side of the equation, find a value that is equal to the square of half of
b
b
.
(
b
2
)
2
=
(
−
7
2
)
2
(
b
2
)
2
=
(
-
7
2
)
2
Add the term to each side of the equation.
x
2
−
7
x
+
(
−
7
2
)
2
=
−
6
+
(
−
7
2
)
2
x
2
-
7
x
+
(
-
7
2
)
2
=
-
6
+
(
-
7
2
)
2
Simplify the equation.
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x
2
−
7
x
+
49
4
=
25
4
x
2
-
7
x
+
49
4
=
25
4
Factor the perfect trinomial square into
(
x
−
7
2
)
2
(
x
-
7
2
)
2
.
(
x
−
7
2
)
2
=
25
4
(
x
-
7
2
)
2
=
25
4
Solve the equation for
x
x
.
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x
=
6
,
1
Make the coefficient of y the same in both equations:
To do this, multiply equation one by 2, and equation two by 5 (this will make the coefficient 10 in both).
14x + 10y = 38
-35x - 10y = -80
Eliminate the y variable by adding the equations from each other
(14x + 10y = 38)
+ (-35x - 10y = -80)
= -21x + 0y = -42
We now have -21x = -42. The y variable has been eliminated.
Solve for x
-21x = -42
Divide both sides by -21 to get x on its own.
x = 2
Substitute x into the equation to find y.
7*2+5y=19
14+5y=19
Subtract 14 from both sides.
5y=19-14
5y=5
Divide by 5 on both sides to get y on its own.
y=5/5
y=1
The answer is (2,1)
Answer:
16.2, 18,2, 20.2, 22.2, 24.2
Step-by-step explanation:
Let
represent an even interger.
Remeber that even intergers have a distance of 2 from each other.
So next four consecutive intergers are
and
Part 2: Five consective intergers have a sum of 101, and qe must find the numbers so
Subtracts 150 each time—
950-150=800 and 800-150=650 and so on and so forth. The number sequence only includes 5 numbers so there is no way to tell if there is a tougher solution.
