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BartSMP [9]
3 years ago
5

Find parametric and symmetric equations of the line through the point (2,1,0) and perpendicular to the plane 5x-3y + 4z = 15

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
6 0

x = 5t + 2
y =  - 3t + 1
z = 4t
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Solve the system of equations y = x + 5 and y = 5x - 11 using a graphical method.
tresset_1 [31]

You can use substitution for this.

x+5 = 5x -11

Combine like terms

16=4x

Divide 4 on both sides to isolate the x

x=4

Plug x=4 to one of the equations

y= 4 +5

Combine like terms

y=9

So the answer is A. (4,9)

I hope this helps you out a bunch hun :)

4 0
3 years ago
Please help me out!!! :) 
Olin [163]

it would be > because the square root of 2 is more than 1.

8 0
3 years ago
Read 2 more answers
Find the prime factorization of 120.
artcher [175]

Answer:

(7/8 - 4/5)^2 = 9/

1600

= 0.005625

Step-by-step explanation:

Subtract: 7/

8

- 4/

5

= 7 · 5/

8 · 5

- 4 · 8/

5 · 8

= 35/

40

- 32/

40

= 35 - 32/

40

= 3/

40

For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(8, 5) = 40. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 8 × 5 = 40. In the next intermediate step, the fraction result cannot be further simplified by canceling.

In words - seven eighths minus four-fifths = three fortieths.

Exponentiation: the result of step No. 1 ^ 2 = 3/

40

^ 2 = 32/

402

= 9/

1600

In words - three-fortieths squared = nine one-thousand six-hundredths.

7 0
3 years ago
A rectangle has an area of 240 square meters and a width of 15 meters.
fredd [130]
Area is found by taking the length time width or A=lw

240=L x 15    divide both sides by 15

Length = 16 meters

3 0
3 years ago
What is the answer to 50/100 f $31.46=
FinnZ [79.3K]

Answer:62.92

Step-by-step explanation:

50/100f=.5f ... 31.46/.5=62.92 ... 62.92=f

4 0
4 years ago
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