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BartSMP [9]
3 years ago
5

Find parametric and symmetric equations of the line through the point (2,1,0) and perpendicular to the plane 5x-3y + 4z = 15

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
6 0

x = 5t + 2
y =  - 3t + 1
z = 4t
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If a pack of paper costs 3.75 including tax, and there is a $20 budget, then the equation to find out the answer would be 3.75p is greater or equal to $20. So the answer would be B. 3.75 would be multiplied by the tax and then applied up to $20. 
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109⁰+118⁰+44⁰=× can you please help​
Paha777 [63]

Answer:

x = 271 degrees

Step-by-step explanation:

6 0
2 years ago
Solve the following equation -6p+7=3(2p-3)-4(-10+4p)<br> a.p=6<br> b.p=5<br> c.p=7<br> d.p=12
Ilia_Sergeevich [38]
Solve for p by simplifying both sides of the equation, then isolating the variable.
p=6
7 0
3 years ago
A toy rocket is launched straight up into the air with an initial velocity of 60 ft/s from a table 3 ft above the ground. If acc
alexdok [17]
The equation is:
h ( t ) = - 16 t² + 60 t + 3
The toy rocket will reach the ground when: h ( t ) = 0
- 16 t² + 60 t + 3 = 0
t _{12} =  \frac{-60+/- \sqrt{3600+192} }{-32}
t 1 = - 0.05
t 2 = 3.8
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C ) 3.80 s

3 0
3 years ago
How many elements does A contains if it has 64 subsets​
Amanda [17]
<h3>Answer:  6</h3>

===========================================================

Explanation:

Rule: If a set has n elements in it, then it will have 2^n subsets.

For example, there are n = 3 elements in the set {a,b,c}. This means there are 2^n = 2^3 = 8 subsets. The eight subsets are listed below.

  1. {a,b,c} .... any set is a subset of itself
  2. {a,b}
  3. {a,c}
  4. {b,c}
  5. {a}
  6. {b}
  7. {c}
  8. { } ..... the empty set

Subsets 2 through 4 are subsets with exactly 2 elements.  Subsets 5 through 7 are singletons (aka sets with 1 element). The last subset is the empty set which is a subset of any set. You could use the special symbol \varnothing to indicate the empty set.

For more information, check out concepts relating to the power set.

-------------------

The problem is asking what value of n will make 2^n = 64 true.

You could guess-and-check your way to see that 2^n = 64 has the solution n = 6.

Another approach is to follow these steps.

2^n = 64\\\\2^n = 2^6\\\\n = 6

Which is fairly trivial.

Or you can use logarithms to solve for the exponent.

2^n = 64\\\\\text{Log}\left(2^n\right)=\text{Log}\left(64\right)\\\\n*\text{Log}\left(2\right)=\text{Log}\left(64\right)\\\\n=\frac{\text{Log}\left(64\right)}{\text{Log}\left(2\right)}\\\\n\approx\frac{1.80617997398389} {0.30102999566399} \ \text{ ... using base 10 logs}\\\\n\approx5.99999999999983\\\\

Due to rounding error, we don't land exactly on 6 even though we should.

5 0
2 years ago
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