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andreyandreev [35.5K]
3 years ago
5

Five is 1/10 of what

Mathematics
1 answer:
Marysya12 [62]3 years ago
7 0
Five is 1/10 of what
50
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X3= one over eight what's the answer for that?
Black_prince [1.1K]
X^3 = 1/8
x^3 = (1/2)^3
    x = 1/2

hope it helps
6 0
3 years ago
Raise <br> n<br> to the 6th <br> power,<br> then add 5 to the result
aleksley [76]
Except there are values you want to substitute into the expression, this is what your answer looks like:

n^{6}+5
7 0
3 years ago
The distance between City A and City B is 250 miles. A length of 2.1 feet represents this distance on a certain wall map. City C
tigry1 [53]

Answer:

650 miles

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

5 0
3 years ago
Read 2 more answers
Help me please i put 15 points i think that means it gives you 7 or 8 points??
castortr0y [4]

Answer:

Mean: 0.15125

Median: 0.05

Mode: .05

Range: 0.495

Hope this helps!

3 0
3 years ago
MATH HELP!!! 100PTS!!!
Lostsunrise [7]

Answer:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Step-by-step explanation:

<u>Given functions</u>:

  p(x)=2x-4

  r(x)=\dfrac{6x-1}{9x+1}

Solve for p(x) = r(x):

\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

<u>Quadratic Formula</u>

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0

Therefore:

a=18, \quad b=-40, \quad c=-3

Substitute the values of a, b and c into the <u>quadratic formula</u> and solve for x:

\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}

Therefore, the solutions are:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0
1 year ago
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