Answer:
E is not a subspace of 
Step-by-step explanation:
E is not a subspace of
In order to see this, we must find two points (a,b), (c,d) in E such that (a,b) + (c,d) is not in E.
Consider
(a,b) = (1,1)
(c,d) = (-1,-1)
It is easy to see that both (a,b) and (c,d) are in E since 1*1>0 and (1-)*(-1)>0.
But (a,b) + (c,d) = (1-1, 1-1) = (0,0)
and (0,0) is not in E.
By the way, it can be proved that in any vector space all sub spaces must have the vector zero.
Answer:
5.48
Step-by-step explanation:
add 2.98 1.75 and 0m75
The probability that a randomly selected runner has a time less than or equal to 3 hours and 20 minutes is 0.16 or 16%.
<h3>What is normally distributed data?</h3>
Normally distributed data is the distribution of probability which is symmetric about the mean.
The mean of the data is the average value of the given data.
The standard deviation of the data is the half of the difference of the highest value and mean of the data set.
The times of the runners in a marathon are normally distributed, with
- Mean of 3 hours and 50 minutes
- Standard deviation of 30 minutes.
Refere the probabiliity table attached below. The probability of Z being inside the 1 Standard daviation of mean is 0.84.
The probability of runner selected with time less than or equal to 3 hours and 20 minutes,

Thus, the probability that a randomly selected runner has a time less than or equal to 3 hours and 20 minutes is 0.16 or 16%.
Learn more about the normally distributed data here;
brainly.com/question/6587992
Answer:
Standard form: 
Center: 
Radius:
Step-by-step explanation:
The equation of a circle in the standard form is

Where the point (h, k) is the center of the circle
To transform this equation
this equation in the standard form we use the method of square.
First, we group similar variables

Divide both sides of equality by 4

Now we complete square for variable x.
Take the coefficient "b" that accompanies the variable x and divide by 2. Then, elevate the result to the square:

Now add
on both sides of the equality

Factor the expression and simplify the independent terms


Then

and the center is 
radius