Answer:
if the stone makes 150 revolution per minute, the tension force of the string on the stone is
The second matrix ![\left[\begin{array}{ccc}-6&3&12\\0&15&-24\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-6%263%2612%5C%5C0%2615%26-24%5Cend%7Barray%7D%5Cright%5D)
represents the triangle dilated by a scale factor of 3.
Step-by-step explanation:
Step 1:
To calculate the scale factor for any dilation, we divide the coordinates after dilation by the same coordinated before dilation.
The coordinates of a vertice are represented in the column of the matrix. Since there are three vertices, there are 2 rows with 3 columns. The order of the matrices is 2 × 3.
Step 2:
If we form a matrix with the vertices (-2,0), (1,5), and (4,-8), we get
![\left[\begin{array}{ccc}-2&1&4\\0&5&-8\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%261%264%5C%5C0%265%26-8%5Cend%7Barray%7D%5Cright%5D)
The scale factor is 3, so if we multiply the above matrix with 3 throughout, we will get the matrix that represents the vertices of the triangle after dilation.
Step 3:
The matrix that represents the triangle after dilation is given by
![3\left[\begin{array}{ccc}-2&1&4\\0&5&-8\end{array}\right] = \left[\begin{array}{ccc}3(-2)&3(1)&3(4)\\3(0)&3(5)&3(-8)\end{array}\right] = \left[\begin{array}{ccc}-6&3&12\\0&15&-24\end{array}\right]](https://tex.z-dn.net/?f=3%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%261%264%5C%5C0%265%26-8%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%28-2%29%263%281%29%263%284%29%5C%5C3%280%29%263%285%29%263%28-8%29%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-6%263%2612%5C%5C0%2615%26-24%5Cend%7Barray%7D%5Cright%5D)
This is the second option.
Answer:
Last 2 terminate
Step-by-step explanation:
9/7 does not terminate: 1.285724285724285724...
5/3 does not terminate: 1.66666666666666666...
3/2 does terminate: 1.5
6/4 same thing as 3/2 = 1.5
C and D terminate.
(24xy^3-16x^2y^2+32x^2y)/8xy
<span><span>(<span><span><span><span><span><span><span>24x</span><span>y^3</span></span>−<span><span>16<span>x^2</span></span><span>y^2</span></span></span>+<span><span>32<span>x^2</span></span>y</span></span>8</span></span>x</span>)</span><span>(y)</span></span><span> =<span><span><span>−<span><span>2<span>x^3</span></span><span>y^3</span></span></span>+<span><span>3<span>x^2</span></span><span>y^4</span></span></span>+<span><span>4<span>x^3</span></span><span>y^<span>2</span></span></span></span></span>
