Hello :
<span>note :
an equation of the
circle Center at the w(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : </span><span>x²+y²-16x+6y+53=0
(</span>x²-16x) +( y²+6y ) +53 = 0
(x² -2(8)x +8² - 8²) +(y² +2(3)x -3²+3² ) +53=0
(x² -2(8)x +8²) - 8² +(y² +2(3)x +3²)-3² +53=0
(x-8)² +( y+3)² = 20
the center is : w(8,-3) and ridus : r = <span>√20</span>
Answer:
x = 2
y = -1
Step-by-step explanation:
2x + y = 3
-2y = 14 - 6x
6x - 2y = 14
2x + y = 3 | ×3 |
6x - 2y = 14 | ×1 |
6x + 3y = 9
6x - 2y = 14
__________--
5y = -5
y = -5/5
y = -1
2x + y = 3
2x + (-1) = 3
2x = 3 + 1
2x = 4
x = 4/2
x = 2
To answer this specific
problem:
A
sample size of 5 for which the sample mean is 20 and the sample
median is 15 would be 9, 12, 15, 25, and 39. I am hoping that this answer has
satisfied your query and it will be able to help you in your endeavor, and if
you would like, feel free to ask another question.
It's should be 5 cause I don't know
For the triangle the value for w would be 11. Im not 100% sure for the other ones though. Sorry
