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Goryan [66]
3 years ago
14

Please show working out, thanks!

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
4 0

Answer:

  C.  x+log(z)

Step-by-step explanation:

Taking the log of the equation gives ...

  log(z) = (x -y)log(1/10) = (x -y)log(10^-1)

  log(z) = (x -y)(-1) = y -x

Adding x gives ...

  x + log(z) = y . . . . . matches choice C

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to advertise o radio,the radio station charges 32naira for the first 10 words and 2naira per word for every additional word.how
o-na [289]

Answer:

Cost for 68 words = 148 naira

Step-by-step explanation:

Given that:

Cost of first ten words = 32 naira

Cost of additional words = 2 naira per word

Let,

x be the number of additional words.

y be the total cost

y = 2x + 32

We have to find the cost for 68 words.

The cost of first 10 words will be 32 naira.

Additional words = 68 - 10 = 58 words

Putting x = 58 in the equation

y = 2(58) + 32

y = 116 + 32

y = 148

Hence,

Cost for 68 words = 148 naira

6 0
3 years ago
Alguien sabe hacer alguno de ellos XFAVOR D;
iris [78.8K]

Answer:

english please...

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is 3/5 times 20
igor_vitrenko [27]
First make 20 into a fraction, then solve; 3/5 · 20/1. 60/5 = 12. Hope that helps!
3 0
3 years ago
A parabola can be drawn given a focus of (-5, -4)(−5,−4) and a directrix of y=-6y=−6. Write the equation of the parabola in any
lord [1]

Answer:

\displaystyle \large{y=\dfrac{x^2}{4} + \dfrac{5x}{2} + \dfrac{5}{4}}

Step-by-step explanation:

Given:

  • Focus = (-5,-4)
  • Directrix = -6

To find:

  • Parabola Equation

Locus of Parabola (Upward/Downward)

\displaystyle \large{\sqrt{(x-a)^2+(y-b)^2} = |y-c|}

Where:

  • (a,b) = focus
  • c = directrix

Hence:

\displaystyle \large{\sqrt{(x+5)^2+(y+4)^2}=|y+6|}

Cancel square root by squaring both sides as we get:

\displaystyle \large{(x+5)^2+(y+4)^2=(y+6)^2}

Solve for y-term:

\displaystyle \large{(x+5)^2=(y+6)^2-(y+4)^2}\\\displaystyle \large{x^2+10x+25=y^2+12y+36-y^2-8y-16}\\\displaystyle \large{x^2+10x+25=4y+20}\\\displaystyle \large{x^2+10x+5=4y}\\\displaystyle \large{y=\dfrac{x^2}{4} + \dfrac{5x}{2} + \dfrac{5}{4}}

4 0
2 years ago
Which value of x is a solution of the inequality?
avanturin [10]

Answer:

3x-3>=9=>

3x>=12=>

x>=4

5 0
3 years ago
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