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Rzqust [24]
3 years ago
15

Please need help fast thank you. The problem is in the picture.

Mathematics
2 answers:
DochEvi [55]3 years ago
7 0
2,3,6,7 hope this helps
egoroff_w [7]3 years ago
4 0

Answer:

Angles 2, 3, 6, 7

Step-by-step explanation:

Since supplementary means to add up to 180 degrees, or a straight angle, we just find which angles are connected with a straight line.

These angles would be Angle 2 and Angle 3.

Since we have a whole figure, we also need to find the corresponding angles for Angle 2 and Angle 3. (Corresponding angles are the same degree as the original angle.)

The Corresponding angles to Angle 2 and Angle 3 are Angle 6 and Angle 7 respectively.

Thus, our answer is Angles 2, 3, 6, and 7.

You might be interested in
Which statement describes how to solve ^3 squareroot x^2-6= ^3 square root 2x+2
aleksley [76]

Answer:

Square both sides and then solves the resulting quadratic equations

Step-by-step explanation:

The equation is 3sqrt(x^2-6)=3sqrt(2x+2)

We can solve this by;

First square both sides;

(3√(x²-6))²=  (3√(2x+2))²

We obtain;

9(x²-6)=9(2x+2)

We simplify to obtain a quadratic equation;

x²-6=2x+2

= x²-2x-8=0

Then we solve the quadratic equation;

x²-4x+2x-8=0  

x(x-4)+2(x-8)=0

(x+2)(x-8)=0

 Values of  x = -2 or 8

4 0
3 years ago
Read 2 more answers
10<br> B<br> с<br> 63°<br> 9<br> A<br> D<br> What is the perimeter of ABCD?<br> perimeter =
zysi [14]
The perimeter is 38 , As you can see each of the sides provided also have another side across from it that’s equal to the length, therefore you you double the size of the sides that were given , and add them two together.
3 0
3 years ago
I need help finding the inverse of this problem
fomenos

y=\sqrt{x-1}+6

(Notice that we always have y\ge6[tex].)Swap [tex]x and y, then solve for y:

x=\sqrt{y-1}+6

x-6=\sqrt{y-1}

(x-6)^2=(\sqrt{y-1})^2

(x-6)^2=y-1

y=(x-6)^2+1 (this is the inverse)

###

This inverse is valid only for x\ge6. Why?

Suppose we take x=0. Then

y=(0-6)^2+1=37

This would suggest that in the original equation, we should get x=37 when y=0. But when we check this, we end up with

0=\sqrt{37-1}+6=\sqrt{36}+6=6+6=12

which is clearly not true.

6 0
3 years ago
Please help this is my question worth 25 points THANKS PLEASE
notsponge [240]

Answer:

sorry but need more info y could be any number

3 0
3 years ago
Read 2 more answers
PLS HELP!! WILL GIVE BRAINLIEST!!
Sergeeva-Olga [200]

Answer:

you do -4 + 54 ÷2 = -29

5 0
2 years ago
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