Please need help fast thank you. The problem is in the picture.

Mathematics

2 answers:

DochEvi [55]3 years ago

7 0

2,3,6,7 hope this helps

egoroff_w [7]3 years ago

4 0

Answer:

Angles 2, 3, 6, 7

Step-by-step explanation:

Since supplementary means to add up to 180 degrees, or a straight angle, we just find which angles are connected with a straight line.

These angles would be Angle 2 and Angle 3.

Since we have a whole figure, we also need to find the corresponding angles for Angle 2 and Angle 3. (Corresponding angles are the same degree as the original angle.)

The Corresponding angles to Angle 2 and Angle 3 are Angle 6 and Angle 7 respectively.

Thus, our answer is Angles 2, 3, 6, and 7.

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Can someone PLEASE help me solve these last 2 problems so I can be done with this math class....really stumped on these 2....

dexar [7]

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speed with wind = 4746/6=791 km/h (sum of airplane and wind)

The speed of airplane is greater than that of the wind, so this is a sum and difference problem.

Greater speed (plane) = (sum+difference)/2=(791+661)/2=726 km/h
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3 years ago

Ben claims that the points (2. 4), (4, 8) and (8, 12) tie on a line. Show that Ben is incorrect.

NeX [460]

Find the slope(s) twice, first the slope of the line connecting (2,4) and (4,8) and then the slope of the line connecting (2,4) and (8,12). If you get different slopes, then it'd be safe for you to conclude that the points do not lie on the same line.

7 0

3 years ago

40 pounds of dog food cost $50 how much would 35 pounds of dog food cost

astraxan [27]

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3 0

3 years ago

Solve for the values of x in the equation: 2^(x) = 4x.

Eva8 [605]

There are two of them.

I don't know a mechanical way to 'solve' for them.

One can be found by trial and error:

x=0 . . . . . 2^0 = 1 . . . . . 4(0) = 0 . . . . . no, that doesn't work
x=1 . . . . . 2^1 = 2 . . . . . 4(1) = 4 . . . . . no, that doesn't work
x=2 . . . . . 2^2 = 4 . . . . . 4(2) = 8 . . . . . no, that doesn't work
x=3 . . . . . 2^3 = 8 . . . . . 4(3) = 12 . . . . no, that doesn't work
x=4 . . . . . 2^4 = 16 . . . . 4(4) = 16 . . . . Yes ! That works ! yay !

For the other one, I constructed tables of values for 2^x and (4x)
in a spread sheet, then graphed them, and looked for the point
where the graphs of the two expressions cross.

The point is near, but not exactly, x = 0.30990693...

If there's a way to find an analytical expression for the value, it must involve
some esoteric kind of math operations that I didn't learn in high school or
engineering school, and which has thus far eluded me during my lengthy
residency in the college of hard knocks. If anybody out there has it, I'm
waiting with all ears.

7 0

3 years ago

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Pachacha [2.7K]

Answer:

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