18 vocabulary words learbed in 2 hours 27 vocabulary words learned in 3 hours Are they equivalent? Why?

Lesechka [4]

${13}^{14}$
Answer: 3.9373764e15

6 0

3 years ago

To determine the area of a rectangle, one strategy is to split the rectangle into smaller pieces, and determine the smaller area

BabaBlast [244]

Say you have a big rectangle. You can split that big rectangle up into little rectangles, say unit rectangles whose areas are 1, and then count up all those little rectangles to find the area of the larger rectangle. So for instance:
I have a rectangle that has an area of 4ft^2
I can split up that rectangle to smaller rectangles of 1ft^2
Then I can count how many smaller rectangles I have and deduce the area of the larger rectangle form that -> 1ft^2 * 4 = 4ft^2

5 0

3 years ago

Carl is boarding a plane. He has 222 checked bags of equal weight and a backpack that weighs 4kg. The total weight of Carl's bag

Advocard [28]

Well first of all, 'kg' means mass, not weight.

If the total mass of all his baggage is 35 kg, and the mass
of his backpack is 4 kg, then the combined mass of all of his
checked bags is (35 - 4) = 31 kg.

If all of his checked bags have the same mass, then the mass
of each one is

(31 kg / 222 bags) = 139.64 grams/bag (rounded)

4 0

3 years ago

Another name for the shape that make up any three-dimensional figure is

frosja888 [35]

Answer:

A

Step-by-step explanation:

5 0

3 years ago

Parallelogram ABCD has the following vertices: A(3,6), B(6,8), C(9,6), and D(6,4). In two ut more complete sentences, explain ho

spin [16.1K]

Explanation:

A rhombus is a parallelogram in which the diagonals are mutual perpendicular bisectors. The coordinates of the vertices can be used to show ...

the diagonals bisect each other
the diagonals are perpendicular

When both these conditions are met, the quadrilateral is a rhombus.

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<h3>Mutual Bisectors</h3>

The diagonals will have the same midpoint (bisect each other) if the sum of the coordinates at the ends of one diagonal is the same as the sum of the end point coordinates of the other diagonal:

A +C = B +D

(3, 6) +(9, 6) = (6, 8) +(6, 4)

(3+9, 6 +6) = (6 +6, 8 +4)

(12, 12) = (12, 12) . . . . . . midpoints are the same; ABCD is a parallelogram

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<h3>Perpendicular</h3>

The diagonals will be perpendicular if the sum of the products of the coordinate differences of their end points is zero.

AC⋅BD = (C -A)⋅(D -B) = (9 -3, 6 -6)⋅(6 -6, 4 -8)

= (6, 0)⋅(0, -4) . . . . . end point differences; we want their dot-product

= (6)(0) +(0)(-4) = 0 +0 = 0 . . . . diagonals are perpendicular

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<em>Additional comment</em>

The midpoints are computed as (A+C)/2 and (B+D)/2. We have multiplied each of them by 2 to simplify the arithmetic. Our resulting sums of (12, 12) must be divided by 2 to get the actual midpoint of the rhombus: (6, 6).

The notion of "dot product" is a vector notion. Two vectors are perpendicular when their dot product is zero. The dot product is the scalar sum of the products of corresponding coordinates.

8 0

2 years ago