Which operation transformed matrix I to matrix II?
2 answers:
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sin(0) = opposite/hypotenuse = 2/5
cos(0) = adjacent/hypotenuse = sqrt21/5
tan(0) = opposite/adjacent = 2/sqrt21 * sqrt21/sqrt21 = 2sqrt21/21
cot(0) = adjacent/opposite = sqrt21/2
sec(0) = hypotenuse/adjacent = 5sqrt21/21
The correct solution is C
Subtract 6 from both sides of the equation
3x + 6 - 6 = 21 - 6
3x = 15
Then divide both sides by 3
x = 5
Subtract 6 from both sides of the equation
3x + 6 - 6 = 21 - 6
3x = 15
Then divide both sides by 3
x = 5