Answer:
Let's define:
A = # of students in group A
B = # of students in group B
C = # of students in group C.
"The total number of students who could attend a field trip is represented by the variable t."
This can be written as:
A + B + C = t.
"The number of students in Group A is less than the number in Group B."
Here we have a strictly "less than", then this is written as:
A < B.
"Group A has 6 students more than 1/4 the total number of students"
A = t/4 + 6
"Group B has 3 less than the total number of students"
B = t - 3.
Then we have the equations:
A + B + C = t.
A = t/4 + 6
B = t - 3.
A < B.
We could replace the second and third equatio in the fourth one, to get:
t/4 + 6 < t - 3.
t/4 + 9 < t
9 < t - t/4
9 < t*(4/4 - 1/4)
9 < t*(3/4)
(4/3)*9 < t
12 < t.
Then we found an inequality that defines the minimum possible value of t,
Number 1 is -23 and number 2 is a
The value of the function h(x + 1) is -x^2 - x + 1
<h3>How to evaluate the function?</h3>
The equation of the function is given as:
h(t) =-t^2 + t + 1
The function is given as:
h(x + 1)
This means that t = x + 1
So, we substitute t = x + 1 in the equation h(t) =-t^2 + t + 1
h(x + 1) =-(x + 1)^2 + (x + 1) + 1
Evaluate the exponent
h(x + 1) =-(x^2 + 2x + 1) + x + 1 + 1
Expand the brackets
h(x + 1) = -x^2 - 2x - 1 + x + 1 + 1
Evaluate the like terms
h(x + 1) = -x^2 - x + 1
Hence, the value of the function h(x + 1) is -x^2 - x + 1
Read more about functions at:
brainly.com/question/1415456
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<u>Complete question</u>
Consider the following function definition, and calculate the value of the function
h(t) = −t2 + t + 1 h(x + 1)
◆ ARITHMETIC PROGRESSIONS ◆
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Check the attachment.
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Answer:
9/8 is simplest form
1.125 is in decimal form
Step-by-step explanation: