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masha68 [24]
3 years ago
8

Find the value of 10!/(10-2)! A) 720 B)80 C)90 D)45

Mathematics
1 answer:
mars1129 [50]3 years ago
6 0

Answer:

\huge \boxed{90}

Step-by-step explanation:

First thing you do is subtract.

10-2=8

\displaystyle \frac{10!}{8!}

Then you cancel the factorials.

\displaystyle \frac{10!}{8}=10\times9

Multiply numbers from left to right to find the answer.

\displaystyle 10\times9=90

\huge \textnormal{90}, which is our answer.

Hope this helps!

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What is 24/16 in simplest form?
-Dominant- [34]
Well you can divide by 8 and it gives you 3/2or  you can divide by 4 and get 6/4 then divide by 2 and get 3/2 either way there both correct
6 0
2 years ago
Avery can run at 10 uph. The bank of a river is represented by the line 4x + 3y = 12, and Avery is at (7, 5). How much time does
Reil [10]
The minimum distance will be along a perpendicular line to the river that passes through the point (7,5)

4x+3y=12

3y=-4x+12

y=-4x/3+12/3

So a line perpendicular to the bank will be:

y=3x/4+b, and we need it to pass through (7,5) so

5=3(7)/4+b

5=21/4+b

20/4-21/4=b

-1/4=b so the perpendicular line is:

y=3x/4-1/4

So now we want to know the point where this perpendicular line meets with the river bank.  When it does y=y so we can say:

(3x-1)/4=(-4x+12)/3  cross multiply

3(3x-1)=4(-4x+12)

9x-3=-16x+48

25x=51

x=51/25

x=2.04

y=(3x-1)/4

y=(3*2.04-1)/4

y=1.28

So now that we know the point on the river that is closest to Avery we can calculate his distance from that point...

d^2=(x2-x1)^2+(y2-y1)^2

d^2=(7-2.04)^2+(5-1.28)^2

d^2=38.44

d=√38.44

d=6.2 units

Since he can run at 10 uph...

t=d/v

t=6.2/10

t=0.62 hours  (37 min 12 sec)

So it will take him 0.62 hours or 37 minutes and 12 seconds for him to reach the river.




8 0
2 years ago
If your salary is $42,500 and your federal income taxes are 10% of your salary, how much money will you owe this year in federal
DiKsa [7]
42,500 X 0.10 = $4250.
You owe $4250!!
3 0
2 years ago
Read 2 more answers
A family has two cars. The first car has a fuel efficuency of 15 miles per gallon of gas and the second has a fuel efficiency of
SVEN [57.7K]

Answer:

x= 35 gallons consumed by 1st car

and y= 40  gallons consumed by 2nd car

Step-by-step explanation:

Fuel efficiency of 1st car = 15 miles per gallon

Fuel efficiency of 2nd car = 35 miles per gallon

Let x= gallons consumed by 1st car

and y= gallons consumed by 2nd car

Total gallons consumed by both cars = 75

so, we can write

x + y = 75

Miles covered by both cars = 1925 miles

and we know, Fuel efficiency of 1st car = 15 miles per gallon

Fuel efficiency of 2nd car = 35 miles per gallon

we can write the equation as

15 x + 35 y = 1925

where x and y are gallons consumed by 1st and 2nd car.

We have two equation now,

x + y = 75                   (1)

15 x + 35 y = 1925     (2)

Multiplying eq(1) with 15 and subtracting eq (1) and 2

15 x + 15 y = 1125

15 x + 35 y = 1925

-       -            -

_______________

0 - 20 y = -800

y= -800 / -20

y = 40

Putting value of y in equation 1

x + y = 75

x + 40 = 75

x= 75 - 40

x = 35

x= 35 gallons consumed by 1st car

and y= 40  gallons consumed by 2nd car

4 0
3 years ago
How can the distributive property be used to find 4 x 875? draw an array.
nika2105 [10]
Easy here
(4x800)+(4x70)+(4x5)
8 0
3 years ago
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