You would multiply by
![\frac{9+\sqrt{14}}{9+\sqrt{14}}](https://tex.z-dn.net/?f=%5Cfrac%7B9%2B%5Csqrt%7B14%7D%7D%7B9%2B%5Csqrt%7B14%7D%7D)
.
When you rationalize the denominator, you multiply by the conjugate of the denominator. The conjugate is the same numbers and radicals, but with the sign of the radical switched.
Answer:
A i think
Step-by-step explanation:
Answer:
![15 {g}^{2} + 15g](https://tex.z-dn.net/?f=15%20%7Bg%7D%5E%7B2%7D%20%20%20%2B%2015g)
Step-by-step explanation:
The given expresion is
![3(5 {g}^{2} + 15g)](https://tex.z-dn.net/?f=3%285%20%7Bg%7D%5E%7B2%7D%20%20%2B%2015g%29)
when we expand this expression we get;
![3(5 {g}^{2} + 15g) = 15 {g}^{2} + 45g](https://tex.z-dn.net/?f=3%285%20%7Bg%7D%5E%7B2%7D%20%20%2B%2015g%29%20%3D%2015%20%7Bg%7D%5E%7B2%7D%20%2B%2045g%20)
Now let us analyze the options:
First:
![15 {g}^{2} + 45g](https://tex.z-dn.net/?f=15%20%7Bg%7D%5E%7B2%7D%20%20%2B%2045g)
This is equivalent to the given expresion.
Second:
![15({g}^{2} + 3g) = 15{g}^{2} + 45g](https://tex.z-dn.net/?f=15%28%7Bg%7D%5E%7B2%7D%20%20%2B%203g%29%20%3D%2015%7Bg%7D%5E%7B2%7D%20%20%2B%2045g)
Also equivalent
Third:
![15g({g} + 3) = 15{g}^{2} + 45g](https://tex.z-dn.net/?f=15g%28%7Bg%7D%20%20%2B%203%29%20%20%3D%2015%7Bg%7D%5E%7B2%7D%20%20%2B%2045g)
Also equivalent
Fourth:
![15 {g}^{2} + 15g \ne 15{g}^{2} + 45g](https://tex.z-dn.net/?f=15%20%7Bg%7D%5E%7B2%7D%20%20%20%2B%2015g%20%20%5Cne%2015%7Bg%7D%5E%7B2%7D%20%20%2B%2045g)
Not equivalent
Answer:
See attachment
Step-by-step explanation:
Factor each expression, as shown in the attachment.
1. Which is a factor of x^2+5x-24
a. (x+4)
b. (x-4)
c. (x+3)
<u>d. (x-3) </u>
2. Which is a factor of x^2+2x-15
<u>a. (x-3)</u>
b. (x+3)
c. (x+15)
d. (x-5)
3. Which is a factor of n^2+3n-54
a. n+6
b. n^2+9
c. n-9
<u>d. n+9</u>