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Nuetrik [128]
3 years ago
10

Write the explicit formula for the following sequence.3, 30, 300, 3000​

Mathematics
1 answer:
masha68 [24]3 years ago
3 0

Answer:

common ratio(r) = 10

place of the term = n

a = 3

now

sequence of 1 term = ar^(n-1)

= 3×10^(1-1)

= 3× 10^0

= 3×1

= 3

sequence of 2 term = ar^(n-1)

= 3×10¹

= 30

and so on

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Simplify 5/15: the numerator and denominator are both multiples of 5, so the fraction can be reduced to 1/3 by dividing the top & bottom by 5. 5/15 of a rectangle is the same as 1/3 of a rectangle.

Compare 1/2 and 5/7:
The simplest way is to ask if 5/7 is more than one half. Half of 7 is 3.5, and 5 is greater than 3.5, so 1/2 < 5/7.
The way that is a little more work is to get a common denominator and make equivalent fractions of 7/14 and 10/14.

Fraction to decimal of 4/5. 4 divided by 5 = 0.8

Decimal to fraction, 0.78:
0.78 = 78 hundredths = 78/100 as a fraction. They usually want fractions in the lowest terms, so divide the numerator and denominator by two, and you have 39/50.

Mixed to improper fraction 5 2/9: multiply the denominator of 9 times the whole number of 5, that equals 45. Add the 2 in the numerator, that is 47. Keep that over 9, because we are trying to figure out how many ninths we have. 5 2/9 = 47/9

Add ‘em 3/5 + 1/2:
Make equivalent fractions with a common denominator. (10 is the least/lowest common denominator). So we are adding 6/10 + 5/10 = 11/10 or 1 1/10.

Improper to mixed, 9/4:
We have 9 fourths. 4 fourths = 1 whole. So we get 2 wholes with 1/4 left over. 9/4 = 2 1/4.

Subtract ‘em, 3/10 - 1/5.
Again, need a common denominator/equivalent fraction. 1/5 = 2/10
3/10 - 2/10 = 1/10

Draw it, 1/3:
The circle is already divided into thirds. Shade one of them in.

Multiply ‘em 2/3 x 5:
Multiply the numerator times the whole number, leave the denominator alone. 2/3 x 5 = 10/3 = 3 1/3 if they want it converted to a mixed number.

Divide ‘em: 8/9 divided by 3 is 8/27

What’s the word?
4 x 1/2 = 2 (what is one half of 4?)

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Your grade? 14/14 = 100%

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4 0
3 years ago
Suppose f'(7)=9 and g(7)= 5. <br> Find h'(7) where h(x) = 3f(x) + 2g(x) + 7<br><br> h'(7)=???
Ratling [72]

Answer:

The value of h'(7) = 44 .

Step-by-step explanation:

Given:

f'(7)=9 and g(7)= 5

We have to find : h'(7)

Also,

⇔ h(x) = 3f(x) + 2g(x) + 7   ...equation (i)

Plugging the value of 'x' = 7 in equation (i) the equation can be re-framed as:

⇔ h(7) = 3f(7) + 2g(7) + 7

⇔ h(7) = 3f(7) + 2g(7) + 7

Now plugging the value of f'=(7)=9 and g(7)=5 in the above equation:

⇔ h(7) = 3(9) + 2(5) + 7

⇔ h(7)=27+10+7

⇔ h(7)=44

So the value of h=(7) = 44 .

6 0
3 years ago
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