Answer: the probability that a randomly selected Canadian baby is a large baby is 0.19
Step-by-step explanation:
Since the birth weights of babies born in Canada is assumed to be normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = birth weights of babies
µ = mean weight
σ = standard deviation
From the information given,
µ = 3500 grams
σ = 560 grams
We want to find the probability or that a randomly selected Canadian baby is a large baby(weighs more than 4000 grams). It is expressed as
P(x > 4000) = 1 - P(x ≤ 4000)
For x = 4000,
z = (4000 - 3500)/560 = 0.89
Looking at the normal distribution table, the probability corresponding to the z score is 0.81
P(x > 4000) = 1 - 0.81 = 0.19
Lol I'm glad to answer your questions :D
So in the last question, it uses the word "per" which basically means you would have to multiply the number of pounds times 1.69
So it would be $1.69a
Answer
The answer is most likely 2 (or C).
Why?
The top of the question simplified into number is 2(5 + 3), which equals 16.
The bottom is (3 +5)1, which equals 8.
Now divide 16/8, which equals 2, and there's your answer.
(Hope this helps you! ^^)
Step-by-step explanation:
1. E
2. D
3. G
4. H
5. F
6. C
7. B
8. J
9. A
10. I
this is the correct answer
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Answer:
$950.51
Step-by-step explanation:
First, find the area of the room, the total square footage, so we know how many tiles to buy. 15*14=210. 210 tiles to buy, $4.25 each. 210*4.25=892.5. If you're not allowed to use a calculator, you can do (210*4)+(210*0.25). The cost before tax is $892.50. What is 6.5% of 892.5? The answer is 58.0125, however, we can't go past the second decimal point or the hundredths digit when deal with money. Rounding to the nearest hundredth, you get $58.01. Add this to cost before tax, 892.50+58.01=950.51. The total cost is $950.51
