Answer:
Therefore the angle of intersection is 
Step-by-step explanation:
Angle at the intersection point of two carve is the angle of the tangents at that point.
Given,

and 
To find the tangent of a carve , we have to differentiate the carve.

The tangent at (0,0,0) is [ since the intersection point is (0,0,0)]
[ putting t= 0]

Again,

The tangent at (0,0,0) is
[ putting t= 0]

If θ is angle between tangent, then






Therefore the angle of intersection is
.
Answer: 3X+4 is the correct answer
Step-by-step explanation:
Answer:
4
cups of Salsa.
Step-by-step explanation:
Flora is making Salsa for a party.
Every 1 cup of chopped tomatoes makes 2
=
cups of Salsa
She uses 1
=
cups of tomatoes
1
cups of tomatoes makes:
×
÷ 1 =
= 4
cups of Salsa.
Answer:
The probability that the cost is kept within budget or the campaign will increase sales is 0.88
Step-by-step explanation:
The probability that the cost is kept within budget (event A) <u>or</u> the campaign will increase sales (event B) is the <u>union</u> of the probability of those two events. By basic properties of probability, this is:
P(A ∪ B) = P(A) + P (B) - P(A ∩ B)
and for independent events:
P(A ∩ B) = P(A) * P(B)
So:
P(A ∪ B) = 0.80 + 0.40 - (0.80*0.40) = 1.20 - 0.32 = 0.88
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> )
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> ) × (-1 + <em>i</em> ) / (-1 + <em>i</em> )
<em>z</em> = (3<em>i</em> × (-1 + <em>i</em> )) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3<em>i</em> + 3<em>i</em> ²) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3 - 3<em>i </em>) / (1 - (-1))
<em>z</em> = (-3 - 3<em>i </em>) / 2
Note that this number lies in the third quadrant of the complex plane, where both Re(<em>z</em>) and Im(<em>z</em>) are negative. But arctan only returns angles between -<em>π</em>/2 and <em>π</em>/2. So we have
arg(<em>z</em>) = arctan((-3/2)/(-3/2)) - <em>π</em>
arg(<em>z</em>) = arctan(1) - <em>π</em>
arg(<em>z</em>) = <em>π</em>/4 - <em>π</em>
arg(<em>z</em>) = -3<em>π</em>/4
where I'm taking arg(<em>z</em>) to have a range of -<em>π</em> < arg(<em>z</em>) ≤ <em>π</em>.