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Svetllana [295]
3 years ago
5

The shoe store expected to sell at least 95 pairs of shoes one weekend, but they only sold 77 pairs. What was the approximate pe

rcent error? Show your work to find the percent error.
Mathematics
2 answers:
Gwar [14]3 years ago
7 0
The error of percentage is the amount of error over the original amount.

In this case it is 22/95  (not 22 over 77 because 77 is not the original amount they expected to sell.   

22/95 = .2315  or 23.2% to the nearest tenth of a percent
Perhaps your teacher just wants 23% as an the approximate error.
GarryVolchara [31]3 years ago
4 0

Answer:

18.9%

Step-by-step explanation:

The error of percentage is the amount of error over the original amount.

First, we subtract 95 from 77 to get 18.

Divide 18 by 95 to get approx. 0.189 then convert to percent which is approx.18.9%

The approximate percent error is 18.9%

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inna [77]
I’m pretty sure it’s 3 and a 2
8 0
3 years ago
What is the value of y in the parallelogram below?<br> G<br> 108<br> 3y<br> D<br> E
Arlecino [84]

Answer:

C

Step-by-step explanation:

In a parallelogram, consecutive angles are supplementary, sum to 180° , so

3y + 108 = 180 ( subtract 108 from both sides )

3y = 72 ( divide both sides by 3 )

y = 24 → C

5 0
3 years ago
Through: (2,2), parallel to y=x+42)
shtirl [24]

Answer:

y=x

Step-by-step explanation:

We want a line parallel to y =x+42

The slope of y =x+42 is 1

Parallel lines have the same slope

We have the slope m=1 and a point (2,2)

We can use point slope form to write a line

y-y1 = m(x-x1)

y-2 = 1(x-2) point slope form

Changing to slope intercept form

y-2 = x-2

Add 2 to each side

y-2+2 = x-2+2

y=x

3 0
3 years ago
The diameter of a sphere is 16 cm. What is the sphere's volume? Round to the nearest tenth.
ohaa [14]

Answer:

V ≈ 2144.70 cm^3

Step-by-step explanation:

Radius is going to be used instead of the diameter. Half of 16 is 8, and so that will be the value that shall be used.

V = (4/3)\pi (8)^3

V ≈ 2144.66 cm^3

V ≈ 2144.70 cm^3

5 0
3 years ago
What is the fifth square root of x^16
melamori03 [73]
The fifth square root as in a^(1/2)^(1/2)^(1/2)^(1/2)^(1/2)

Well that is equal to a^((1/2)^5) or a^(1/32)

Since a=x^16 in this case and the rule (b^a)^c=b^(a*c) we have:

(x^16)^(1/32)

x^(16/32)

x^(1/2) or if you prefer

√x


8 0
3 years ago
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