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Aloiza [94]
3 years ago
15

Andy buys x cakes. Betty buys 4 times as many cakes as Andy. Colin buys 3 more cakes than Andy. Each cake costs 65p. The total c

ost of the cakes is £52.65. How many cakes did each person buy?
Mathematics
1 answer:
Paladinen [302]3 years ago
8 0

Answer:

Each cake cost £ 13.00

Step-by-step explanation:

We were given that, each cake costs 65p or £ 0.65

Andy buys x cakes.

Andy's cost is

£0.65x


Betty buys 4 times as many cakes as  Andy.

Betty's cost is

£0.65(4x)

£2.60x


Colin buys 3 more cakes than Andy

Colin's cost is

£0.65(x+3)


The total cost of the cakes is £ 52.65.


This implies that,

0.65x+0.65(x+3)+2.60x=52.65


We expand to get,

0.65x+0.65x+1.95+2.60x=52.65


We group like terms to get,


0.65x+0.65x+2.60x=52.65-1.95

This gives us,

0.65x+0.65x+2.60x=52.65-1.95


This implies that,


3.9x=50.7


x=\frac{50.7}{3.9}


x=13


Therefore each cake cost £ 13.00






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Step-by-step explanation:

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a = ?

b = ?

c = ?

Determining the values of a, b, and c

Using the mid-point formula

m\:=\:\left(\frac{x_1+x_2}{2},\:\frac{y_1+y_2}{2},\:\frac{z_1+z_2}{2}\right)

  • As the point R(-3, a, -1) is the midpoint of the line segment jointing the points P(1,2,b)  and Q(c,-7,4), so
  • m = R = (x, y, z) = (-3, a, -1)

Using the mid-point formula

m\:=\:\left(\frac{x_1+x_2}{2},\:\frac{y_1+y_2}{2},\:\frac{z_1+z_2}{2}\right)

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(x₁, y₁, z₁) = (1, 2, b) = P

(x₂, y₂, z₂) = (c, -7, 4) = Q

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substituting the value of (x₁, y₁, z₁) = (1, 2, b) = P,   (x₂, y₂, z₂) = (c, -7, 4) = Q, and m = (x, y, z) = (-3, a, -1) = R in the mid-point formula

m\:=\:\left(\frac{x_1+x_2}{2},\:\frac{y_1+y_2}{2},\:\frac{z_1+z_2}{2}\right)

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<u>Determining 'b'</u>

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b = -2-4

b = -6

Therefore, the values are:

  • a = -5/2
  • b = -6
  • c = -7
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