100g of ammonia releases 271.18 kJ of heat.
<u>Explanation:</u>
Given:
N₂ reacts with H₂
The reaction is:
2N₂ + 3H₂ → 2NH₃ + 92.2 kJ
According to the balanced reaction:
2 X 17g of ammonia releases 92.2 kJ of heat
34g of ammonia releases 92.2 kJ of heat
100g of ammonia will release = 
kJ of heat
= 271.18 kJ
Therefore, 100g of ammonia releases 271.18 kJ of heat.
Answer:
R3 <= 0.083
Step-by-step explanation:
f(x)=xlnx,
The derivatives are as follows:
f'(x)=1+lnx,
f"(x)=1/x,
f"'(x)=-1/x²
f^(4)(x)=2/x³
Simialrly;
f(1) = 0,
f'(1) = 1,
f"(1) = 1,
f"'(1) = -1,
f^(4)(1) = 2
As such;
T1 = f(1) + f'(1)(x-1)
T1 = 0+1(x-1)
T1 = x - 1
T2 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2
T2 = 0+1(x-1)+1(x-1)^2
T2 = x-1+(x²-2x+1)/2
T2 = x²/2 - 1/2
T3 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2+f"'(1)/6(x-1)^3
T3 = 0+1(x-1)+1/2(x-1)^2-1/6(x-1)^3
T3 = 1/6 (-x^3 + 6 x^2 - 3 x - 2)
Thus, T1(2) = 2 - 1
T1(2) = 1
T2 (2) = 2²/2 - 1/2
T2 (2) = 3/2
T2 (2) = 1.5
T3(2) = 1/6 (-2^3 + 6 *2^2 - 3 *2 - 2)
T3(2) = 4/3
T3(2) = 1.333
Since;
f(2) = 2 × ln(2)
f(2) = 2×0.693147 =
f(2) = 1.386294
Since;
f(2) >T3; it is significant to posit that T3 is an underestimate of f(2).
Then; we have, R3 <= | f^(4)(c)/(4!)(x-1)^4 |,
Since;
f^(4)(x)=2/x^3, we have, |f^(4)(c)| <= 2
Finally;
R3 <= |2/(4!)(2-1)^4|
R3 <= | 2 / 24× 1 |
R3 <= 1/12
R3 <= 0.083
Answer:
Step-by-step explanation:
he has 1/4 remaining as he has only used 3/4
Answer:
60°
Step-by-step explanation:
This questions tests our knowledge on arcs and arc measures.
-Arc measure is the angle that an arc makes with the circle's center.
-The arc measure is proportional to the arc.
#The sum of the 3 arcs is x+2x+3x=6x
Given a circle has 360°, the arc measurement x can be calculated as:
![[x+2x+3x]=360\textdegree\\\\6x=360\textdegree\\\\x=60\textdegree](https://tex.z-dn.net/?f=%5Bx%2B2x%2B3x%5D%3D360%5Ctextdegree%5C%5C%5C%5C6x%3D360%5Ctextdegree%5C%5C%5C%5Cx%3D60%5Ctextdegree)
Hence, the arc measurement x is 60°
Answer:
B and D are the answer's.
Step-by-step explanation:
