To figure out this problem, you need to find the surface area of a triangular prism.
a=5ft
b=5ft
c=6ft
h=8ft
A= (a*h) + (b*h) + (c*h) + 1/2√-a⁴ + 2(a*b)² + 2(a*c) - b⁴ + 2(b*c) - c⁴
=152 square feet
Answer:
3x2y−3xy+12x−12
Take out 3xy common from first two terms and 12 from last two terms.
3xy(x−1)+12(x−1)
(x−1)(3xy+12)
9514 1404 393
Answer:
a square 175 m on a side
Step-by-step explanation:
Let x and y represent the sides of the rectangle. Then the perimeter is ...
P = 2(x + y) = 700
x + y = 350 . . . . . . . divide by 2
y = 350 -x . . . . . . . . subtract x
The area of the fenced field is ...
A = xy
A = x(350 -x)
This is a quadratic function that has zeros at x = 0 and x = 350. The axis of symmetry is x = (0 +350)/2 = 175. The vertex (maximum area) is on the axis of symmetry, so corresponds to x = 175. The y-value there is ...
y = 350 -x = 350 -175 = 175
That is, the maximum area will be obtained when the fenced area is a square. Each side of the square is 175 m, which is 1/4 of the total length of the fence.
The dimensions of the space are 175 m by 175 m.