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beks73 [17]
4 years ago
9

Solve the equation for h: A= 1/2h(b1+b2)

Mathematics
1 answer:
iVinArrow [24]4 years ago
5 0

Answer:

  h = 2A/(b1 +b2)

Step-by-step explanation:

Divide by the coefficient of h.

  A = h(b1 +b2)/2

  2A/(b1 +b2) = h

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 Total: 20
 The percentage sought is then:
 (3/20) * (100) = 15%
 Answer:
 
percentage of the total students chose skateboarding is:
 
D.) none of these

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Ty has a $30 gift card. He already bought a $9 book, and wants to buy $3
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I am a 3-digit number. If rounded off to the nearest hundreds. I become 500. If rounded off to the nearest tens, I become 540. I
dimulka [17.4K]

Answer:

535 is the cirrext answer

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3 years ago
What is this plz answer
Anna11 [10]

25.2 \div 4 = 6.3
5.69 \div 7 = 0.813
22.5 \div 15 = 1.5
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3 years ago
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A ½in diameter rod of 5in length is being considered as part of a mechanical linkagein which it can experience a tensile loading
Evgesh-ka [11]

Answer:

a. Maximum Load = Force = 27085.09 N

b. Maximum Energy = 3.440 Joules

Step-by-step explanation:

Given

Rod diameter = ½in = 0.5in

Length = 5in

Young's modulus = 15.5Msi

By applying the 0.2% offset rule,

The maximum load the rod can hold before it gets to breaking point is given as follows by taking the strain as 0.2%

Young Modulus = Stress/Strain ------- Make Stress the Subject of Formula

Stress = Strain * Young Modulus

Stress = 0.2% * 15.5

Stress = 0.002 * 15.5

Stress = 0.031Msi

Calculating the area of the rod

Area = πr² or πd²/4

Area, A = 22/7 * 0.5^4 / 4

A = 22/7 * 0.25 / 4

A = 5.5/28

A = 0.1964in²

The maximum load that the rod would take before it starts to permanently elongate is given by

Force = Stress * Atea

Force = 0.031Msi * 0.1964in²

Force = 31Ksi * 0.1964in²

Force = 6.089Ksi in²

Force = 6.089 * 1000lbf

Force = 6089 lbf

1 lbf = 4.4482N

So, Force = 6089 * 4.4482N

Force = 27085.09 N

b.

Using Strain to Energy Formula

U = V×σ²/2·E

Where V = Volume

V = Length * Area

V = 5 in * 0.1964in²

V = 0.982in³

σ = Stress = 0.031Msi

= 0.031 * 1000Ksi

= 31Ksi

= 31 * 1000psi

= 31000psi

E = Young Modulus = 15.5Msi

= 15.5 * 1000Ksi

= 15.5 * 1000 * 1000psi

= 15500000psi

So,

Energy = 0.982 * 31000²/ ( 2 * 15500000)

Energy = 943,702,000/31000000

Energy = 30.442in³psi

------- Converted to ftlbf

Energy = 2.537 ftlbf

-------- Converted to Joules

Energy = 3.440 Joules

7 0
4 years ago
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