The student does a work of 500 Newton meter on the box.
Step-by-step explanation:
Given,
Weight of box of books = force = 200 N
Distance the box is lifted = 2.5 m
Work done = Force * distance
Work done =
Work done = 500 Newton-meter
Newton meter is same as Joule.
Work done = 500 Joules
The student does a work of 500 Newton meter on the box.
Keywords: multiplication, work done
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Option 3:
m∠ABC = 66°
Solution:
Given and ABH is a transversal line.
m∠FAB = 48° and m∠ECB = 18°
m∠ECB = m∠HCB = 18°
<u>Property of parallel lines: </u>
<em>If two parallel lines cut by a transversal, then the alternate interior angles are equal.</em>
m∠FAB = m∠BHC
48° = m∠BHC
m∠BHC = 48°
<u>Exterior angle of a triangle theorem: </u>
<em>An exterior angle of a triangle is equal to the sum of the opposite interior angles.</em>
m∠ABC = m∠BHC + m∠HCB
m∠ABC = 48° + 18°
m∠ABC = 66°
Option 3 is the correct answer.