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podryga [215]
3 years ago
11

A quality control engineer at a potato chip company tests the bag filling machine by weighing bags of potato chips. Not every ba

g contains exactly the same weight. But if more than 15% of bags are over-filled then they stop production to fix the machine. They define over-filled to be more than 1 ounce above the weight on the package. The engineer weighs 100 bags and finds that 21 of them are over-filled. He plans to test the hypotheses: H0: p = 0.15 versus Ha: p > 0.15 (where p is the true proportion of overfilled bags). What is the test statistic?
Mathematics
1 answer:
Roman55 [17]3 years ago
4 0

Answer:

The test statistic is Z=\frac{\hat{p}-0.15}{\sqrt{0.15(0.85)/100}} and the observed value 1.68

Step-by-step explanation:

We have a large sample size n = 100, the point estimate for the true proportion of overfilled bags p is given by \hat{p} = 21/100. The test statistic is given by Z=\frac{\hat{p}-0.15}{\sqrt{0.15(0.85)/100}} which is distributed as a standard normal variable approximately because we have a large sample. The observed value for the test statistic in this case is z=\frac{0.21-0.15}{\sqrt{0.15(0.85)/100}} = 1.68

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Jake has a rectangular garden that measures 12 feet by 14 feet. He wants to increase the area by 50% and plans to increase each
emmasim [6.3K]

<em>In order to increase the area of a rectangular garden that measures 12 feet by 14 feet by 50% Jake must increase each dimension by equal lengths, x:</em>

x\approx 2.9ft

<h2>Explanation:</h2><h2 />

First of all, let's calculate the area of the original rectangular garden:

A=b\times h \\ \\ b:base \\ \\ h:height \\ \\ \\ b=12ft \\ \\ h=14ft \\ \\ \\ A=12(14) \\ \\ A=168ft^2

Jake wants to increase the area by 50%, so the new area would be:

A'=168(1.5) \\ \\ A'=252ft^2

He wants to increase the area by 50% and plans to increase each dimension by equal lengths, x, so this is represented by the figure below, therefore:

(12+x)(14+x)=252 \\ \\ 168+12x+14x+x^2-252=0 \\ \\ x^2+26x-84=0 \\ \\ \\ Using \ quadratic \ formula: \\ \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ a=1 \\ \\ b=26 \\ \\ c=-84 \\ \\ \\ x=\frac{-26 \pm \sqrt{26^2-4(1)(-84)}}{2(1)} \\ \\ x=\frac{-26 \pm \sqrt{1012}}{2} \\ \\ \\ Two \ solutions: \\ \\ x_{1}=-13+\sqrt{253} \approx 2.9\\ \\ x_{2}=-13-\sqrt{253} \approx -28.9 \\ \\ x_{2} \ is \ discarded \ because \ it \ can't \ be \ negatives

Finally:

<em>In order to increase the area of a rectangular garden that measures 12 feet by 14 feet by 50% Jake must increase each dimension by equal lengths, x:</em>

x\approx 2.9ft

<h2>Learn more:</h2>

Dilation: brainly.com/question/10945890

#LearnWithBrainly

6 0
3 years ago
What is the slope of the line that passes through the points (3,1) and (-2,5)
sweet-ann [11.9K]
The gradient formula is:

m = y2 - y1/ x2 - x1 

> m = 5 - 1 /-2 -3
>> m = 4/-5x
8 0
3 years ago
What is the volume of a ball if the diameter if the ball is 6 inches? Leave your answer in terms of π.
kap26 [50]
<span>Volume  = 4/3*pi*r^3
As diameter = 6 inches
Radius = Diameter / 2
Radius = 6/ 2
Radius = 3 inches
Putting the value of r in the formula :
 =4/3*pi*3^3
</span><span> =4/3*pi*27
 </span>= 36*pi 
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<span>B) V = 36 π cubic inches , is the correct answer.</span>
7 0
2 years ago
Read 2 more answers
Write a rule for the nth term of the arithmetic sequence:<br><br> a11= 50, d = 7
ivolga24 [154]

Answer:

Required rule for n^{th} is a_{n}=7n-27.

Step-by-step explanation:

Given that,

a_{11} = 50,\  \  d=7

From the question: we have to write the n^{th} term of Arithmetic sequence.

Arithmetic Sequence or Arithmetic progression (A.P) : It is a sequence which possess that difference between of two successive sequence is always constant.

                a_{1} ,a_{2},a_{3},a_{4}.....................a_{n-1},a_{n}

                                        where, a_{1} is the first term of A.P

                                                     d is the common difference.

                                                     a_{n} is the last term or general term.

The above sequence to be in A.P then their common difference should be equal.

          d=a_{2}-a_{1} =a_{3}-a_{2}=a_{4} -a_{3} ..........................a_{n}-a_{n-1}

Now, Formula of General Term is a_{n}=a+(n-1)d

So,                                                    a_{11}= a+(11-1)d\\        a_{11} = a+10d

 Substituting the value of   a_{11} = 50,\  \  d=7 we get,

                                                         50=a+10\times7\\50=a+70\\a=-20

Then General term (a_{n}) of given data is

                                                         a_{n}=-20+(n-1)7\\a_{n}=-20+7n-7\\a_{n}=7n-27

Therefore, Required rule for n^{th} is a_{n}=7n-27.

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%28%28x%20-%201%29%20%5Cdiv%203%20%29%20-%202%20%5Cleqslant%20%28%285%20-%202x%29%20%5Cdiv%206
sergejj [24]

Answer:

x ≤ \frac{19}{4}

Step-by-step explanation:

Given

\frac{x-1}{3} - 2 ≤ \frac{5-2x}{6}

Multiply through by 6 to clear the fractions

2(x - 1) - 12 ≤ 5 - 2x ← distribute and simplify left side

2x - 2 - 12 ≤ 5 - 2x

2x - 14 ≤ 5 - 2x ( add 2x to both sides )

4x - 14 ≤ 5 ( add 14 to both sides )

4x ≤ 19 ( divide both sides by 4 )

x ≤ \frac{19}{4}

6 0
3 years ago
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