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If the average of x and y is 11 and the average of x, y and z is 5, then the value of z is -7
Given,
The average of x and y = 11
We know average = Sum of the terms / Number of terms
Then, the equation will become
x+y =11×2
x+y =22
Average of x, y and z = 5
x+y+z = 5×3
x+y+z =15
Substitute the value of x+y
22+z=15
z =15-22
x = -7
Hence, If the average of x and y is 11 and the average of x, y and z is 5, then the value of z is -7
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Answer:
A. y = 2x -9
B. y = -1/2x +1
Step-by-step explanation:
The given line is in slope-intercept form
y = mx + b
where m is the slope. For your given line, the slope is 2.
A. A parallel line will have the same slope. It is convenient to start with a point-slope form of the equation for the line:
y = m(x -h) +k . . . . . for slope m through point (h, k)
You want the equation of the line through (4, -1) with slope 2, so its equation is ...
y = 2(x -4) -1
Simplifying to slope-intercept form, this becomes ...
y = 2x -8 -1
y = 2x -9
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B. A perpendicular line will have a slope that is the opposite of the reciprocal of the slope of the given line. That slope is ...
m = -1/2
As above, the point-slope form of the perpendicular line is ...
y = -1/2(x -4) -1
y = -1/2x +1 . . . . . after simplification
