Answer:
Condition A.
A rectangle with four right angles
There can be many quadrilaterals satisfying this condition.
Condition B.
A square with one side measuring 5 inches
There can be only one quadrilateral satisfying this condition.
Condition C.
A rhombus with one angle measuring 43°
There can be many quadrilaterals satisfying this condition.
Condition D.
A parallelogram with one angle measuring 32°
There can be many quadrilaterals satisfying this condition.
Condition E.
A parallelogram with one angle measuring 48° and adjacent sides measuring 6 inches and 8 inches.
There can be only one quadrilateral satisfying this condition.
Condition F.
A rectangle with adjacent sides measuring 4 inches and 3 inches.
There can be only one quadrilateral satisfying this condition
Step-by-step explanation:
It is 14 because 8= 6to-2 and 3to-3is 6 so both together is 14
hope this helps
5(x^2 - 14x + 258/5)
= 5((x-7)^2 -49+258/5)
= 5((x-7)^2 + 13/5)
= 5(x-7)^2 + 13
I belive this is how it should be done
Answer:
The consecutive odd integers are (15, 17, 19) or (-17, -15, -13).
Step-by-step explanation:
Let the three consecutive odd integers be: 
The condition given is:
![4[x-2+x+x+2]=3x(x+2)-765](https://tex.z-dn.net/?f=4%5Bx-2%2Bx%2Bx%2B2%5D%3D3x%28x%2B2%29-765)
Solve this for <em>x</em> as follows:
![4[x-2+x+x+2]=3x(x+2)-765\\4\times 3x=3x^{2}+6x-765\\3x^{2}-6x-765=0\\x^{2}-2x-255=0\\x^{2}-17x+15x-255=0\\x(x-17)+15(x-17)=0\\(x-17)(x+15)=0](https://tex.z-dn.net/?f=4%5Bx-2%2Bx%2Bx%2B2%5D%3D3x%28x%2B2%29-765%5C%5C4%5Ctimes%203x%3D3x%5E%7B2%7D%2B6x-765%5C%5C3x%5E%7B2%7D-6x-765%3D0%5C%5Cx%5E%7B2%7D-2x-255%3D0%5C%5Cx%5E%7B2%7D-17x%2B15x-255%3D0%5C%5Cx%28x-17%29%2B15%28x-17%29%3D0%5C%5C%28x-17%29%28x%2B15%29%3D0)
- If
then the value of <em>x</em> is 17.
The odd numbers are:
- If
then the value of <em>x</em> is -15.
The odd numbers are:
Thus, the consecutive odd integers are (15, 17, 19) or (-17, -15, -13).
Answer:
the easy way is to take notes and study them before a test
Step-by-step explanation:
i took this lesson a few weeks ago
