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NISA [10]
3 years ago
6

The distance from your house to the park is represented by the expression "5x + 4 more than 2 − 2x." The distance from the park

to the school is represented by the expression "2x − 2 less than 3x − 10." Find a single expression that represents the distance traveled if you pass through the park on your way to school.
Mathematics
1 answer:
Neko [114]3 years ago
6 0

Answer:

The distance from the house to the school is equal to (4x-2)

Step-by-step explanation:

Let

A-----> the distance from house to the park

B----> the distance from the park to the school

C----> the distance from house to the school

so

C=A+B

we know that

A=(2-2x)+(5x+4)

B=(3x-10)-(2x-2)

so

Find the the value of C

C=(2-2x)+(5x+4)+(3x-10)-(2x-2)

C=(4x-2)

therefore

The distance from the house to the school is equal to (4x-2)

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Y-5 = -3 (x+2) in standard form
expeople1 [14]

Answer:

maybe y - -3x = -11?

Step-by-step explanation:

im rushing so i may have did it wrong sorry

8 0
3 years ago
Becky bought a bag of mixed chocolates that have either a toffee or nut center. Her and four friends pulled out the first eleven
denpristay [2]

Answer

Part A

Probability that the next chocolate will have a toffee center = (8/11)

Part B

Expected number of chocolates with nut centers = 18 nut centers

Part C

Probability of the picking three consecutive chocolates with nut centers

= (27/1331)

= 0.0203

Explanation

The first 11 chocolates had 8 toffee and 3 nut centers.

The result from these first 11 picks will be used to calculate the rest of the probability or make predictions.

So, for the first part of the question.

Probability that the next chocolate will have a toffee center

= (8/11)

Part B

If there are 66 chocolates left in the bag, how many do you expect to have a nut center?

Probability of picking a chocolate with nut center = p = (3/11)

Number of chocolates in total = n = 66

Expected number of chocolates with nut centers

= np

= (66) (3/11)

= 18 nut centers

Part C

What is the probability that the next 3 pulled do have a nut in the center?​

Probability of picking a chocolate with nut center = (3/11)

Probability of the picking three consecutive chocolates with nut centers

= (3/11) × (3/11) × (3/11)

= (27/1331)

= 0.0203

Hope this Helps!!!

3 0
9 months ago
5 watermelons 6 cantaloupes cost $54. 4 watermelons and 8 cantaloupes $56. how much is a cantaloupe
GREYUIT [131]

Answer:

A cantaloupe costs $4

Step-by-step explanation:

Watermelons = W

Cantaloupes = C

Write given statements as equations

5W + 6C = 54

4W + 8C = 56

Simplify the second equation

4W + 8C = 56

Subtract 8C from both sides of the equation

4W = 56 - 8C

Divide both sides of the equation by 4

W = 14 - 2C

Substitute into second equation

5W + 6C = 54

5(14 - 2C) + 6C = 54

Multiply 5(14 - 2C)

70 - 10C + 6C = 54

Add -10C + 6C

70 - 4C = 54

Add 4C to both sides of the equation

70 = 54 + 4C

Subtract 54 from both sides of the equation

16 = 4C

Divide both sides of the equation by 4

C = 4

A cantaloupe costs $4

5W + 6(4) = 54

Multiply 6(4)

5W + 24 = 54

Subtract 24 from both sides of the equation

5W = 30

Divide both sides of the equation by 5

W = 6

A cantaloupe costs $4

A watermelon costs $6

Hope this helps :)

8 0
3 years ago
The full question.the full question you were asking for ​
Svetlanka [38]

Answer:

I'm getting stuck by

= lim \:  \:  \:  \:  \:  \:   \frac{ {h}^{ \frac{1}{5} } }{h}  \\ h > 0

Sorry I can't help you out, if you find the answer through FP lmk

7 0
1 year ago
Find the fifth roots of 243(cos 240° + i sin 240°).
Mazyrski [523]

Answer:

See below.

Step-by-step explanation:

Fifth root of 243 = 3,

Suppose r( cos Ф + i sinФ) is the fifth root of 243(cos 240 + i sin 240),

then r^5( cos  Ф  + i sin  Ф )^5 = 243(cos 240 + i sin 240).

Equating equal parts and using de Moivre's theorem:

r^5 =243  and  cos  5Ф  + i sin  5Ф = cos 240 + i sin 240

r = 3 and  5Ф = 240 +360p so Ф =  48 + 72p

So Ф = 48, 120, 192, 264, 336  for   48 ≤ Ф < 360

So there are 5 distinct solutions given by:

3(cos 48 + i sin 48),

3(cos 120 + i sin 120),

3(cos 192 + i sin 192),

3(cos 264 + i sin 264),

3(cos 336 + i sin 336).. (Answer).

7 0
3 years ago
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