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Elena-2011 [213]
3 years ago
7

6. Solve P = C + rC for r.

Mathematics
2 answers:
slavikrds [6]3 years ago
4 0

Answer:

r=c2pi ok

Step-by-step explanation:

that the answer

kiruha [24]3 years ago
4 0

Answer:

p = c + rc \\ p - c = rc \\  \frac{p - c}{c}  = r \: or \: r =  \frac{p - c}{c}

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Can someone please help my with my work.
Aleksandr [31]

Answer:

X+0.375=y

Step-by-step explanation:

6 0
3 years ago
Write the explicit formula for the geometric sequence 2, 8, 32, 128
Alja [10]
The first term, a, is 2.  The common ratio, r, is 4.  Thus,

a_(n+1) = 2(4)^(n).

Check:  What's the first term?  Let n=1.  Then we get 2(4)^1, or 8.  Is that correct?  No.

Try this instead:

a_(n) = a_0*4^(n-1).  Is this correct?    Seeking the first term (n=1), does this formula produce 2?      2*4^0 = 2*1 = 2.  YES.

The desired explicit formula is   a_(n) = a_0*4^(n-1), where n begins at 1.


3 0
3 years ago
Hi people here hi hi oya
oksian1 [2.3K]

Answer:

Hi How are you doing today???

5 0
3 years ago
Read 2 more answers
Erika is working on solving the exponential equation 50x = 17; however, she is not quite sure where to start. using complete sen
seropon [69]

The equation be 50x = 17 then the value of x = 17/50.

<h3>How to find the value of x?</h3>

To estimate the value of x, bring the variable to the left side and bring all the remaining values to the right side. Simplify the values to estimate the result.

Let the equation be 50x = 17

Diving both sides of the equation by 50, we get

50x/50 = 17/50

x = 17/50

Therefore, the value of x = 17/50.

To learn more about the expression refer to:

brainly.com/question/723406

#SPJ4

3 0
2 years ago
A trough is 8 feet long and has perpendicular cross section in the shape of an isosceles triangle (point down) with base 1 foot
murzikaleks [220]

Answer:

Dh/dt  = 0.082 ft/min

Step-by-step explanation:

As a perpendicular cross section of the trough is in the shape of an isosceles triangle the trough has a circular cone shape wit base of  1 feet and height     h = 2 feet.

The volume of a circular cone is:

V(c)  = 1/3 * π*r²*h

Then differentiating on both sides of the equation we get:

DV(c)/dt   = 1/3* π*r² * Dh/dt   (1)

We know that DV(c) / dt   is  1 ft³ / 5 min      or     1/5  ft³/min

and  we are were asked how fast is the water rising when the water is 1/2 foot deep. We need to know what is the value of r at that moment

By proportion we know

r/h  ( at the top of the cone  0,5/ 2)   is equal to  r/0.5  when water is 1/2 foot deep

Then      r/h   =   0,5/2   =  r/0.5

r  =  (0,5)*( 0.5) / 2        ⇒   r  =  0,125 ft

Then in equation (1) we got

(1/5) / 1/3* π*r² =  Dh/dt

Dh/dt  = 1/ 5*0.01635

Dh/dt  = 0.082 ft/min

4 0
3 years ago
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