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2 years ago

6. Solve P = C + rC for r.

Mathematics

2 answers:

slavikrds [6]2 years ago

4 0

Answer:

r=c2pi ok

Step-by-step explanation:

that the answer

kiruha [24]2 years ago

4 0

Answer:

$p = c + rc \\ p - c = rc \\ \frac{p - c}{c} = r \: or \: r = \frac{p - c}{c}$

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2 years ago

Pioneer company has given an aptitude test to 71 potential job applicants. The test score had an average of 81 and a standard de

Agata [3.3K]

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Follows are the solution to the given points:

Step-by-step explanation:

In point A:

$\to df = n - 1 = 71-1= 70$

In point B:

$\to t = \frac{(x -X)}{s} = \frac{(93-81)}{8} = \frac{12}{8}= 1.5$

In point C:

For df = 70, the top 5% critical t score

tcrit = 1.666914479

Thus,

$\to 1.666914479 = \frac{(x - 81)}{8}\\\\\to 1.666914479 \times 8 = (x - 81)\\\\\to 13.335315832 = (x - 81)\\\\\to 13.335315832 +81 =x \\\\\to x= 94.335315832$

In point D:

For df = 70, the top 5% critical t score

tcrit = -1.666914479

$\to -1.666914479 = \frac{(x - 81)}{8}\\\\\to -1.666914479 \times 8= (x - 81)\\\\\to -13.335315832= (x - 81)\\\\\to -13.335315832+81 = x \\\\\to x = 67.664684168\\\\$

In point E:

The lower cutoff is 0.10 in the center, which would be around 80 %. The critical point therefore is

tcrit = -1.293762898

$\to -1.293762898 = \frac{(x-81)}{8}\\\\\to -1.293762898 \times 8= (x-81) \\\\\to -1.293762898 \times 8= (x-81) \\\\\to -10.350103184=x-81\\\\\to -10.350103184+81=x\\\\\to x=70.649896816$

In point F:

The lower cutoff is 0.90 in the center, which would be around 80 %. The critical point therefore is

tcrit = 1.293762898

$\to 1.293762898 = \frac{(x-81)}{8}\\\\\to 1.293762898 \times 8= x-81\\\\\to 10.350103184 =x-81\\\\\to 10.350103184 +81=x\\\\\to x = 91.350103184\\$

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3 years ago