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Goryan [66]
3 years ago
9

Twice a number is 12 more than five times the number

Mathematics
1 answer:
inna [77]3 years ago
4 0
N x 2 = 12 + 5n
2n - 5n = 12
-3n = 12
3n = -12
n = -4
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What are the correct answers?
DochEvi [55]

Step-by-step Answer:

Situations with dot-products.

dot-product of vectors A<xa,ya>, B<xb,yb>

is defined as A.B=xa*xb + ya+yb

Note that the result is a scalar even though A and B are both vectors.

Q1 dot product is positive

Q2 dot product is negative

The dot product is also equal to the length of the projection of the unit vector of one onto the other, multiplied by the magnitudes.  This implies that the sign will be positive if the angle between the vectors is acute, and negative if the angle between them is obtuse.  That makes the first two proposed answers (A, B) correct.

Q3 dot product equals 0

Since the projection of any vector onto another perpendicular to it is zero, so the dot product of two perpendicular vectors always equal zero.  That makes the third proposed answer (E) correct.

Q4 dot product equals the product of the vectors' magnitudes.

The earlier statement

"The dot product is also equal to the length of the projection of the unit vector of one onto the other, multiplied by the magnitudes."

makes the fourth statement true if the unit vector projected onto the other remains a unit vector, i.e. when the two vectors are parallel (D)

Q5 dot product equals opposite of the product of the vectors.

To have the dot product's absolute value equal the product of the magnitudes, the vectors must be parallel.  If the dot product is positive, then the vectors are parallel and pointing in the same direction, as in Q4.

If the dot product is negative, meaning that is the opposite of the product of the magnitudes (themselves are always positive or zero), then the vectors are parallel, but in the opposing directions.

There is no correct answer for this case, which is definitely NOT "not possible".  The closest one is (D) vectors are parallel, but answer is incomplete.

Q6 dot product is greater than the product of the vectors' magnitudes.

I do not see a possible case for this to happen.


6 0
3 years ago
Question 7 Multiple Choice Worth 1 points)
pychu [463]

Answer:

6 square units is the answer

8 0
3 years ago
The metric system has several advantages that include all of the following except _____.
4vir4ik [10]

Answer:

Only 10 base units to learn

Step-by-step explanation:

The metric system is a decimal based system developed to be universally acceptable by making use of base units from obtained from nature and the use of prefixes for multiples and submultiples of the base units, decimal ratios, which allows easy representation of quantities, as well as having a coherent structure of base and derived units which are obtained from the base units

During conversion in the metric system, which is decimal based, it is only required to move the decimal point

The prefixes which are used to specify multiples and submultiples are the same through out

The decimal system is based on the powers of ten

The number of base units to learn are 7 including; 1. Meter (m), 2. Kilogram (kg), 3. Second (s), 4. Ampere (A), 5. Kelvin (k), 6. Candela (cd), and 7. mole (mol)

Therefore the metric system has several advantages that include all of the following except; Only 10 base units to learn

4 0
3 years ago
You want to know how many miles harriet went. which situation about her exercise best represents the inequality 15x 7 &gt; 52?
Lady_Fox [76]
The answer is either a or d but we know she did all of this for more than 52 minutes.
8 0
3 years ago
Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z
dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0  } \atop {0}; Otherwise} \right.

The value of constant C can be obtained as:

\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1

\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz  }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ])  } \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}]  } \, dy  }) \, dx =1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0  }) \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}]   } \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}]  } \, dx = 1

50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1

50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1

50C[0+\frac{1}{0.5} ] =1

100C = 1 ⇒ C = \frac{1}{100}

C = 0.01

3 0
3 years ago
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