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nordsb [41]
3 years ago
8

What is the expansion of (3+x)^4

Mathematics
1 answer:
Vlad1618 [11]3 years ago
6 0

Answer:

\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81

Step-by-step explanation:

Considering the expression

\left(3+x\right)^4

Lets determine the expansion of the expression

\left(3+x\right)^4

\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i

a=3,\:\:b=x

=\sum _{i=0}^4\binom{4}{i}\cdot \:3^{\left(4-i\right)}x^i

Expanding summation

\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}

i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0

i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1

i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2

i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3

i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4

=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4

=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4

as

\frac{4!}{0!\left(4-0\right)!}\cdot \:\:3^4x^0:\:\:\:\:\:\:81

\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1:\quad 108x

\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2:\quad 54x^2

\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3:\quad 12x^3

\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4:\quad x^4

so equation becomes

=81+108x+54x^2+12x^3+x^4

=x^4+12x^3+54x^2+108x+81

Therefore,

  • \left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81
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2 years ago
5(x - 3) = 2(x + 6) + 3x
Verdich [7]
The first one is
5x-15=2x+12+3x
5x-2x-3x=12+15
0=27

The second one is
6.5x-7.75x=-12+14.5
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Divide both sides by - 1.25
X=. 02

The third one is
K-10=3
K=13
The second part of the third one is
-|k-10|=3
-k+10=3
-k=3+10
-k=13
Divide both sides by negative
K=-13

The fourth one is
4n+32=56
4n=56-32
4n=24
Divide both sides by 4
N=6
The second part to that one is
-4|n+8|=56
-4n-32=56
-4n=88
Divide both sides by - 4
N=22

The fifth one is
N+7-6=8
N=8-7+6
N=1+6
N=7
The second part to this one is
-|n+7|-6=8
-n-7-6=8
-n=8+7+6
-n=21
Divide both sides by negative
N=-21

The last one is
5x-7-3=9
5x=9+7+3
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Divide both sides by 5
X=19 over 5
The second part to this one is
-|5x-7|-3=9
-5x+7-3=9
-5x=9-7+3
-5x=5
Divide both sides by - 5
X=-1
I hope this helps you out.
3 0
3 years ago
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