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Inessa05 [86]
3 years ago
6

What math property is 8 times 1/8

Mathematics
1 answer:
Dmitry [639]3 years ago
5 0

Answer:

i think it is the multiplicative identiy property

Step-by-step explanation:

You might be interested in
4x + 9y = 4
saw5 [17]

Answer:

x=101/65, y=-16/65. (101/65, -16/65).

Step-by-step explanation:

4x+9y=4

9x+4y=13

----------------

9(4x+9y)=9(4)

-4(9x+4y)=-4(13)

------------------------

36x+81y=36

-36x-16y=-52

----------------------

65y=-16

y=-16/65

4x+9(-16/65)=4

4x-144/65=4

4x=4+144/65

4x=404/65

x=(404/65)/4=101/65

x=101/65, y=-16/65.

7 0
3 years ago
Solve each system of equations <br> X^2+y^2+18x+29=0<br> X+y=1
tatyana61 [14]

Answer:

two solutions : (-3;4)  and (-5;6)

Step-by-step explanation:

hello :

X²+y²+18x+29=0    ..(1)

X+y=1 ...(2)

by (2) : y = 1 - x

put this value in (1) : x² +(1-x)² +18x+29 = 0

x² +1 +x² -2x+18x +29 =0

2x²+16x +30 = 0

x²+8x+15 =0

delta = b²-4ac     a=1   b=8   c = 15

delta = (8)²-4(1)(15)=64-60 =4 = 2²

X1=(-8+2)/2 = - 3

X2=(-8-2)/2 = - 5

case 1 : x = -3    y = 1 - (-3) = 4

case 2 : x = -5    y = 1 - (-5) = 6

8 0
3 years ago
What is the result of 5 divided by 1/5?
blagie [28]

Answer:

15 divided by 1/5 is equal to 1.

4 0
3 years ago
Read 2 more answers
Identify the expression with nonnegative limit values. More info on the pic. PLEASE HELP.
marshall27 [118]

Answer:

\lim _{x\to 2}\:\frac{x-2}{x^2-2}\\\\  \lim _{x\to 11}\:\frac{x^2+6x-187}{x^2+3x-154}\\\\ \lim _{x\to \frac{5}{2}}\left\frac{2x^2+x-15}{2x-5}\right

Step-by-step explanation:

a) \lim _{x\to 3}\:\frac{x^2-10x+21}{x^2+4x-21}=\lim \:_{x\to \:3}\:\frac{\left(x-7\right)\left(x-3\right)}{\left(x+7\right)\left(x-3\right)}=\lim \:_{x\to \:3}\:\frac{x-7}{x+7}=\frac{3-7}{3+7}=-\frac{4}{10}=-\frac{2}{5}

b) \lim _{x\to -\frac{3}{2}}\left(\frac{2x^2-5x-12}{2x+3}\right)=\lim \:_{x\to -\frac{3}{2}}\:\frac{\left(2x+3\right)\left(x-4\right)}{\left(2x+3\right)}=\lim \:\:_{x\to \:-\frac{3}{2}}\:\left(x-4\right)=-\frac{3}{2}-4\\ \\ \lim _{x\to -\frac{3}{2}}\left(\frac{2x^2-5x-12}{2x+3}\right)=-\frac{11}{2}

c) \lim _{x\to 2}\:\frac{x-2}{x^2-2}=\frac{2-2}{\left(2\right)^2-2}=\frac{0}{4-2}=0

d) \lim _{x\to 11}\:\frac{x^2+6x-187}{x^2+3x-154}=\lim _{x\to 11}\:\frac{\left(x-11\right)\left(x+17\right)}{\left(x-11\right)\left(x+14\right)}=\lim _{x\to 11}\:\frac{\left(x+17\right)}{\left(x+14\right)}=\frac{11+17}{11+14}=\frac{28}{25}

e) \lim _{x\to 3}\:\frac{x^2-8x+15}{x-3}=\lim \:_{x\to \:3}\:\frac{\left(x-3\right)\left(x-5\right)}{x-3}=\lim _{x\to 3}\left(x-5\right)=3-5=-2

f) \lim _{x\to \frac{5}{2}}\left(\frac{2x^2+x-15}{2x-5}\right)=\lim \:_{x\to \:\frac{5}{2}}\frac{\left(2x-5\right)\left(x+3\right)}{2x-5}=\lim \:\:_{x\to \:\:\frac{5}{2}}\left(x+3\right)=\frac{5}{2}+3=\frac{11}{2}

4 0
3 years ago
which of the following expresses the coordinates of the foci of the conic section shown below? (x-2)^2/4+(y+5)^2/9
elena55 [62]

Step-by-step explanation:

\frac{(x - 2) {}^{2} }{4}  +  \frac{(y + 5) {}^{2} }{9}  = 1

This is the equation of the ellipse. Since the denominator is greater for the y values, we have a vertical ellipse. Remember a>b, so a

The formula for the foci of the vertical ellipse is

(h,k+c) and (h,k-c).

where c is

Our center (h,k) is (2, -5)

{c}^{2}  =  {a}^{2}  -  {b}^{2}

Here a^2 is 9, b^2 is 4.

{c}^{2}  = 9 - 4

{c}^{2}  = 5

c =  \sqrt{5}

So our foci is

(2, - 5 +  \sqrt{5} )

and

(2, - 5 -  \sqrt{5} )

6 0
1 year ago
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