Factorise <br> 84xy+196x-36y-84

You want to find out whether caffeine mitigates the effect of alcohol on reaction time. To study this, you administer to your su

Ymorist [56]

Answer:

First Question

lower limit of 9 mph $j = 8.5 \ mph$

upper limit of 9 mph $q = 9.5 \ mph$

Second Question

lower limit of 120 pounds is $i = 119.9 \ pounds$

upper limit of 120 pounds is $l = 120.1 \ pounds$

Third Question

lower limit of 187 pounds is $a = 186.75 \ pounds$

upper limit of 187 pounds is $b = 187.25 \ pounds$

Step-by-step explanation:

From the question we are told that

The amount of beer administered is three 12-ounce beers

The amount of coffee administered is two cups of coffee

The speed limit is 60-mph

The smallest unit of scale is 1 mph

The first subject scores 9 mph

Generally given that the smallest unit of scale is 1 mph then the deviation of 9 mph will be by $\frac{1}{2} \ mph$

Hence the lower limit of 9 mph is

$j = 9 - 0.5$

$j = 8.5 \ mph$

And the upper limit of 9 mph is

$q = 9 + 0.5$

$q = 9.5 \ mph$

Generally given that the measuring weight on a scale that is accurate to the nearest 0.2 pound then 120 pounds will deviate by $\frac{1}{0.2} \ pounds$

Hence the lower limit of 120 pounds is

$i = 120 - 0.1$

$i = 119.9 \ pounds$

And the upper limit of 120 pounds is

$l = 120 + 0.1$

$l = 120.1 \ pounds$

Generally given that the measuring weight on a scale that is accurate to the nearest 0.5 pound then 187 pounds will deviate by $\frac{1}{0.5} \ pounds = 0.25 \ pounds$

Hence the lower limit of 120 pounds is

$a = 187 - 0.25$

$a = 186.75 \ pounds$

And the upper limit of 120 pounds is

$b = 187 + 0.25$

$b = 187.25 \ pounds$

5 0

4 years ago

How to Graph the solution set -2(x+6)>-4x

arsen [322]

Answer:

use desmos online graphing calculator

Step-by-step explanation:

it helps alot :)

5 0

4 years ago

I arrive at a bus stop at a time that is normally distributed with mean 08:00 and SD 2 minutes. My bus arrives at the stop at an

Nimfa-mama [501]

Answer:

0.0485 = 4.85% probability that you miss the bus.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When two normal distributions are subtracted, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

In this question:

We have to find the distribution for the difference in times between when you arrive and when the bus arrives.

You arrive at 8, so we consider the mean 0. The bus arrives at 8:05, 5 minutes later, so we consider mean 5. This means that the mean is:

$\mu = 0 - 5 = -5$

The standard deviation of your arrival time is of 2 minutes, while for the bus it is 3. So

$\sigma = \sqrt{2^2 + 3^2} = \sqrt{13}$

The bus remains at the stop for 1 minute and then leaves. What is the chance that I miss the bus?

You will miss the bus if the difference is larger than 1. So this probability is 1 subtracted by the pvalue of Z when X = 1.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1 - (-5)}{\sqrt{13}}$

$Z = \frac{6}{\sqrt{13}}$

$Z = 1.66$

$Z = 1.66$ has a pvalue of 0.9515

1 - 0.9515 = 0.0485

0.0485 = 4.85% probability that you miss the bus.

5 0

3 years ago

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule

Sergeeva-Olga [200]

Answer:

First term: 5

Fourth term: 5 1/2

Tenth term: 6 1/2

Step-by-step explanation:

Let's find the first, fourth and tenth terms of the arithmetic sequence described by the given rule:

A(n) = 5 + (n-1) (1/6)

First term:

A(1) = 5 + (1-1) (1/6)

A(1) = 5 + (0) (1/6)

A(1) = 5

Fourth term:

A(4) = 5 + (4-1) (1/6)

A(4) = 5 + (3) (1/6)

A(4) = 5 + 3/6 = 5 3/6 = 5 1/2 (simplifying)

Tenth term:

A(10) = 5 + (10-1) (1/6)

A(10) = 5 + (9) (1/6)

A (10) = 5 + 9/6 = 6 3/6 = 6 1/2 (simplifying)

5 0

3 years ago

(7.8×10^7) + (9.9×10^7)

Hatshy [7]

(7.8×10⁷)+(9.9×10⁷)
(7.8×10000000)+(9.9×10000000)
(78000000)+(99000000)
177000000

8 0

3 years ago

Factorise 84xy+196x-36y-84