Answer:
a. f(-1)=12
b. f(2t)=16t²-6t+5
c. f(t-2)=4t²-19t+27
Step-by-step explanation:
For a, b, c, we are given an input. We plug that into f(x) to find our answers.
a. f(-1)=12
f(-1)=4(-1)²-3(-1)+5
f(-1)=4+3+5
f(-1)=12
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b. f(2t)=16t²-6t+5
f(2t)=4(2t)²-3(2t)+5
f(2t)=4(4t²)-6t+5
f(2t)=16t²-6t+5
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c. f(t-2)=4t²-19t+27
f(t-2)=4(t-2)²-3(t-2)+5
f(t-2)=4(t²-4t+4)-3t+6+5
f(t-2)=4t²-16t+16-3t+6+5
f(t-2)=4t²-19t+27
Answer:
The chances of landing on blue are 1 in 4, or one fourth. The chances of landing on red are 1 in 4, or one fourth. This problem asked us to find some probabilities involving a spinner.
1.875 cups of flour ... add snap naomi_ful
B
given a quadratic equation in standard form
ax² + bx + c = 0
Then we can describe the nature of the roots using the discriminant
Δ = b² - 4ac
• if b² - 4ac > 0, then 2 real, distinct and irrational roots
• if b² - 4ac > 0 and a perfect square, then real and rational roots
• if b² - 4ac = 0, then real and equal roots
• if b² - 4ac < 0, then roots are not real
for x² + 9x + 14 = 0
with a = 1, b= 9 and c = 14, then
b² - 4ac = 9² - (4 × 1 × 14 ) = 81 - 56 = 25
Since b² - 4ac > 0 and a perfect square, then roots are real and rational
