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2 years ago

Please help me this packet is due at 6 p.m please help me ill give brainilist

Mathematics

2 answers:

Lerok [7]2 years ago

5 0

Answer:

$3. is the answer

Step-by-step explanation:

atroni [7]2 years ago

4 0

So if 5 tickets sold for $15, then I believe one ticket will cost $3.

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Simplify this algebraic expression, please!

sasho [114]

Using the Division Property of Equality you need to divide.

How to get answer:

Reduce the expression by cancelling the common factors.

Factor 3 out of 3y^6.

Cancel the common factor.

Rewrite the expression.

Reduce the expression by cancelling the common factors.

−1⋅14

Last step: Multiply −1 by 14.

Answer: −14

6 0

3 years ago

2/5y + 1/5x - 0.2y - 6 + -2 which are like terms. select all that apply

horrorfan [7]

$\text{Like terms are } \frac{2}{5}y \text{ and } -0.2y$

Solution:

Given that the expression is:

$\frac{2}{5}y + \frac{1}{5}x -0.2y-6+(-2)$

We have to select the like terms

"Like terms" means that terms that has same variables with same exponent and same ( or different ) coefficients

In the given expression, y is a variable

Two terms has y as variable : $\frac{2}{5}y \text{ and } -0.2y$

Here variable "y" is same in both terms and coefficients are different

"x" is also a variable in given expression. But there are no other terms with "x" as variable

So they form a like terms

$\frac{2}{5}y + \frac{1}{5}x -0.2y-6+(-2)\\\\\frac{2}{5}y - 0.2y + \frac{1}{5}x -6 + (-2)$

Thus the like terms are : $\frac{2}{5}y \text{ and } -0.2y$

3 0

3 years ago

Order at the end and help pls

Elena L [17]

Answer:

#4- Descending- 9140, 4593, 3401, 1250

#5- Ascending- 1845, 4478, 7324, 9750

3 0

2 years ago

Please write the solution

GrogVix [38]

Answer:

Step-by-step explanation:

that is the answer to the question above

3 0

2 years ago

The matrix C=[1,-2_-3,7] was used to encode a phrase to [7,-28,-25,-35,-2_-21,107,90,123,17]. Find C^-1 and use it to decode the

posledela

$C= \left[\begin{array}{cc}1&-2\\-3&7\end{array}\right] \\ C^{-1}= \left[\begin{array}{cc}7&2\\3&1\end{array}\right] \\ \left[\begin{array}{cc}7&2\\3&1\end{array}\right] \times \left[\begin{array}{ccccc}7&-28&-25&-35&-2\\-21&107&90&123&17\end{array}\right] \\ =\left[\begin{array}{ccccc}49-42&-196+214&-175+180&-245+246&-14+34\\21-21&-84+107&-75+90&-105+123&-6+17\end{array}\right] \\ =\left[\begin{array}{ccccc}7&18&5&1&20\\0&23&15&18&11\end{array}\right]$
is the required matrix.

6 0

3 years ago