(x^3/y^ 5)^2
power to a power is multiply
x^(3*2)/(y^5*2)
x^6/y^10
C) x to the 6th power over y to the 10th power
T=0 I guess
Hope this helps :)
Sorry if this is wrong
Answer:
x
=
e
y
+
3
−
4
Step-by-step explanation:
Algebra Examples
Popular Problems Algebra Find the Inverse y=e^(x+3)-4
y
=
e
x
+
3
−
4
Interchange the variables.
x
=
e
y
+
3
−
4
Solve for
y
.
Tap for fewer steps...
Since
y
is on the right side of the equation, switch the sides so it is on the left side of the equation.
e
y
+
3
−
4
=
x
Add
4
to both sides of the equation.
e
y
+
3
=
x
+
4
Take the natural logarithm of both sides of the equation to remove the variable from the exponent.
ln
(
e
y
+
3
)
=
ln
(
x
+
4
)
Use logarithm rules to move
y
+
3
out of the exponent.
(
y
+
3
)
ln
(
e
)
=
ln
(
x
+
4
)
The natural logarithm of
e
is
1
.
(
y
+
3
)
⋅
1
=
ln
(
x
+
4
)
Multiply
y
+
3
by
1
.
y
+
3
=
ln
(
x
+
4
)
Subtract
3
from both sides of the equation.
Answer:
X=2y-6
Step-by-step explanation:
Y = 1/2 X+3
Y = X/2+3
Y = X+2•3/2
Y = X+6/2
2y = X+6
2y + (-6) = (X+6) + (-6)
2y-6 = X+6-6
2y-6 = X
Answer: X = 2y-6 I hope it helps....