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uranmaximum [27]
3 years ago
8

Please help fast it’s a test

Mathematics
2 answers:
photoshop1234 [79]3 years ago
4 0

Answer:

The first box is 8 and the second box is 96

Step-by-step explanation:

Hope this helps!

Musya8 [376]3 years ago
3 0
The first box is 8 and the next one is 96
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Someone help pleaseeee
qaws [65]

Answer:

Part A = D

Part B = 5 and 50

Step-by-step explanation:

Part A:

area = 5*4x = 20x

so, 100 \leq 20x \leq  1000

Part B:

to leave it only by x, you divide both sides by 20

100/20 = 5, 1000/20 = 50

which 5\leq x\leq 50

7 0
4 years ago
<img src="https://tex.z-dn.net/?f=%5Clarge%5Csf%5Cfbox%5Cred%7BQuestion%3A-%7D" id="TexFormula1" title="\large\sf\fbox\red{Quest
tamaranim1 [39]

Answer:

  • The function is injective but nor surjective

Step-by-step explanation:

<u>We see that:</u>

  • f(x) = x³

<u>For any x₁ and x₂ ∈ N, </u>

  • f(x) = x₁³ = x₂³ ⇒ x₁ = x₂, both are natural numbers

It it confirmed one-to-one, hence it is injective

<u>Check the surjectivity:</u>

f(x) = y ∈ N

  • x³ = y
  • y = ∛x

<u>Let y = 2, then:</u>

  • 2 = x³
  • x = ∛2 ∉ N

Since x is not natural, the function is not surjective

6 0
3 years ago
Read 2 more answers
The vertices of quadrilateral PQRS are P(4, 5), Q(6, 6), R(9, 4), and S(7, 2). Write a paragraph proof to determine whether quad
Svetlanka [38]
The vector PQ is Q-P = (2, 1). The vector SR is R-S = (2, 2). One is not a multiple of the others, so the vectors are not parallel. In a parallelogram, these vectors would be identical. PQRS is not a parallelogram.

5 0
3 years ago
Question 1
Tpy6a [65]

Answer:

C is the correct answer

7 0
3 years ago
Read 2 more answers
*Silly and/or spam answers will not be tolerated*
stepladder [879]

Answer:

-1/8

Step-by-step explanation:

lim x approaches -6     (sqrt( 10-x) -4) / (x+6)

Rationalize

   (sqrt( 10-x) -4)      (sqrt( 10-x) +4)

    ------------------- * -------------------

       (x+6)                 (sqrt( 10-x) +4)

We know ( a-b) (a+b) = a^2 -b^2

a= ( sqrt(10-x)   b = 4    

(10-x) -16

-------------------

(x+6) (sqrt( 10-x) +4)    

-6-x

-------------------

(x+6) (sqrt( 10-x) +4)

Factor out -1 from the numerator

-1( x+6)

-------------------

(x+6) (sqrt( 10-x) +4)

Cancel x+6 from the numerator and denominator

-1

-------------------

(sqrt( 10-x) +4)

Now take the limit

lim x approaches -6    -1/ (sqrt( 10-x) +4)

                                      -1/ (sqrt( 10- -6) +4)

                                      -1/ (sqrt(16) +4)

                                      -1 /( 4+4)

                                        -1/8

5 0
3 years ago
Read 2 more answers
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