I'm pretty sure its −1 7/8
Hi!!Could you please explain your question more?
The probability of winning is 0.44 .
<u>Step-by-step explanation:</u>
Here it's given that , You enter a chess tournament where your probability of winning a game is 0.3 against half the players (call them type 1), 0.4 against a quarter of the players (call them type 2), and 0.5 against the remaining quarter of the players (call them type 3). You play a game against a randomly chosen opponent. More precisely :
Now, we choose a random opponent and we need to find probability of winning which is possible as :
<u>1. player chosen from type1</u>
<u>2. player chosen from type2</u>
<u>3. player chosen from type3</u>
Combining all cases we get :
⇒ 
⇒ 
⇒ 
∴ The probability of winning is 0.44 .
Alright, let's solve the second one because why not:

Let's then work on getting x by itself:


And that's your answer!
1/2bh
1/2b4 = 18
b4= 36
b= 9 yards