Answer:
Step-by-step explanation:
1) Let the random time variable, X = 45min; mean, ∪ = 30min; standard deviation, α = 15min
By comparing P(0 ≤ Z ≤ 30)
P(Z ≤ X - ∪/α) = P(Z ≤ 45 - 30/15) = P( Z ≤ 1)
Using Table
P(0 ≤ Z ≤ 1) = 0.3413
P(Z > 1) = (0.5 - 0.3413) = 0.1537
∴ P(Z > 45) = 0.1537
2) By compering (0 ≤ Z ≤ 15) ( that is 4:15pm)
P(Z ≤ 15 - 30/15) = P(Z ≤ -1)
Using Table
P(-1 ≤ Z ≤ 0) = 0.3413
P(Z < 1) = (0.5 - 0.3413) = 0.1587
∴ P(Z < 15) = 0.1587
3) By comparing P(0 ≤ Z ≤ 60) (that is for 5:00pm)
P(Z ≤ 60 - 30/15) = P(Z ≤ 2)
Using Table
P(0 ≤ Z ≤ 1) = 0.4772
P(Z > 1) = (0.5 - 0.4772) = 0.0228
∴ P(Z > 60) = 0.0228
Answer:
D
Step-by-step explanation:
Here, we want to get the value of x;
To get this, we simply use one of the circle angle and arc properties
Mathematically;
arc MN = 2 * arc MLN
3x + 22 = 134/2
That will be;
3x + 22 = 67
3x = 67-22
3x = 45
x = 45/3
x = 15
Answer:
Step-by-step explanation:
n²+2n+1 = (n+1)(n+1)
n²-8n-9 = (n+1)(n-9)
the least common denominator for these two rational expressions is :
(n+1)(n-9)
Given:
The figure of two quadrilaterals.
In 
In 
To find:
Whether the figures are congruent, similar or neither.
Solution:
Ratio of corresponding sides are:
Similarly,
And,
Clearly, 
.
All corresponding sides are not proportional.
Therefore, the figures are neither similar nor congruent. Hence, third option is correct.
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
