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loris [4]
3 years ago
11

A 32-bit computer has two selector channels and one multiplexor channel. Each selector channel supports two hard disks and two D

VDs units. The multiplexor channel has two printers, five VDT terminals connected to it. Assume the following transfer rates.
Disk drive 800 Kbytes/s
DVD drive 700 Kbytes
Printer 10 Kbytes/s
VDT 2 Kbytes/s

Estimate the maximum aggregate I/O transfer rate in this system.
Computers and Technology
1 answer:
Anit [1.1K]3 years ago
7 0

Answer:

Maximum Aggregate I/O Transfer Rate = 1630kb/s

Explanation:

Given

Transfer rate of

Disk Drive = 800Kb/s

DVD Drive = 700Kb/s

Printer = 10Kb/s

VDT = 2Kb/s

Units

DVD = 2

Hard Disk = 2

Printers = 2

VDT Channels = 5

Only one device at a time can be serviced on a selector channel

Both cannot be active at a time

So, the device with higher transfer rate will be granted access (Disk Drive, 800Kb/s)

Maximum aggregate I/O transfer rate in this system is calculated by:

Summation of transfer rate of each device

= 800 * 2 + 2 * 10 + 5 * 2

= 1600 + 20 + 10

= 1630kb/s

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