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makkiz [27]
3 years ago
13

What is the advantage of video conferecing

Computers and Technology
2 answers:
Svet_ta [14]3 years ago
7 0

some advantages of video conferencing include:

• you can talk no matter how far you are from the person

•you won’t have to go somewhere to talk

•there is no cost if you need to travel far

Vlad [161]3 years ago
4 0

Answer:

the advantage of video conferencing is that you don't have to travel a long distance just to have a conference. You can stay at home and you can do it over face time and then you will get all the information that you need without even having to sit there in a room after you traveled X amount of distance  

Explanation:

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Disadvantages of the divisional organization structure are _____. each division is able to operate independently from the parent
Fantom [35]

Answer:

Disadvantages:

1. A division may feel separated from the parent company because it has too much independence

2. This feeling of separation may lead to the division only worrying about meeting it's goals and objectives and not the companies as a whole

3. This system may be more expensive to operate and cannot share resources with other divisions

Explanation:

8 0
2 years ago
The memory capacity in bits for performing the operation y = f (x) using the table lookup method, where x is an 8-bit number and
Flura [38]

Answer:

The page field is 8-bit wide, then the page size is 256 bytes.

Using the subdivision above, the first level page table points to 1024 2nd  level page tables, each pointing to 256 3rd page tables, each containing 64 pages. The program's address space consists of 1024 pages, thus we need we need 16 third-level page tables. Therefore we need 16 entries in a 2nd level page table, and one entry in the first level page table. Therefore the size is: 1024 entries for the first table, 256 entries for the 2nd level page table, and 16 3rd level page table containing 64 entries each. Assuming 2 bytes per entry, the space required is 1024 * 2 + 256 * 2 (one second-level paget table) + 16 * 64 * 2 (16 third-level page tables) = 4608 bytes.

First, the stack, data and code segments are at addresses that require having 3 page tables entries active in the first level page table. For 64K, you need 256 pages, or 4 third-level page tables. For 600K, you need 2400 pages, or 38 third-level page tables and for 48K you need 192 pages or 3 third-level page tables. Assuming 2 bytes per entry, the space required is 1024 * 2 + 256 * 3 * 2 (3 second-level page tables) + 64 * (38+4+3)* 2 (38 third-level page tables for data segment, 4 for stack and 3 for code segment) = 9344 bytes.

Explanation:

16 E the answer

5 0
3 years ago
Which of the following scanning technique attackers use to bypass firewall rules, logging mechanism, and hide themselves as usua
cestrela7 [59]

Answer: Stealth scanning technique

Explanation:

Stealth scanning technique consist of the following types of scans :

1. FIN scan

2. X- MAS tree scan

3. NULL scan

The FIN scan responds by considering port open if response in received for its packet sent with the fin flag else considered closed.

The X-MAS tree scan fires up by setting a  TCP packet with URG, PUSH, FIN flags and the port is considered open if no response.

NULL scans sends null packet and considers it to be an open port.

Stealth scanning techniques considers to get some response from the network with out actually using a handshaking and is used to bypass firewall rules, logging mechanism, and hide themselves as usual network traffic.

3 0
4 years ago
Oxnard Casualty wants to ensure that their e-mail server has 99.98 percent reliability. They will use several independent server
sattari [20]

Answer:

The smallest number of servers required is 3 servers

<em />

Explanation:

Given

Reliability = 99.98\%

Individual Servers = 95\%

Required

Minimum number of servers needed

Let p represent the probability that a server is reliable and the probability that it wont be reliable be represented with q

Such that

p = 95\%\\

It should be noted that probabilities always add up to 1;

So,

p + q = 1'

Subtract p from both sides

p - p + q = 1 - p

q = 1 - p

Substitute p = 95\%\\

q = 1 - 95\%

Convert % to fraction

q = 1 - \frac{95}{100}

Convert fraction to decimal

q = 1 - 0.95

q = 0.05

------------------------------------------------------------------------------------------------

<em>To get an expression for one server</em>

The probabilities of 1 servers having 99.98% reliability is as follows;

p = 99.98\%

Recall that probabilities always add up to 1;

So,

p + q = 1

Subtract q from both sides

p + q - q = 1 - q

p = 1 - q

So,

p = 1 - q = 99.98\%

1 - q = 99.98\%

Let the number of servers be represented with n

The above expression becomes

1 - q^n = 99.98\%

Convert percent to fraction

1 - q^n = \frac{9998}{10000}

Convert fraction to decimal

1 - q^n = 0.9998

Add q^n to both sides

1 - q^n + q^n= 0.9998 + q^n

1 = 0.9998 + q^n

Subtract 0.9998 from both sides

1 - 0.9998 = 0.9998 - 0.9998 + q^n

1 - 0.9998 = q^n

0.0002 = q^n

Recall that q = 0.05

So, the expression becomes

0.0002 = 0.05^n

Take Log of both sides

Log(0.0002) = Log(0.05^n)

From laws of logarithm Loga^b = bLoga

So,

Log(0.0002) = Log(0.05^n) becomes

Log(0.0002) = nLog(0.05)

Divide both sides by Log0.05

\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}

\frac{Log(0.0002)}{Log(0.05)} = n

n = \frac{Log(0.0002)}{Log(0.05)}

n = \frac{-3.69897000434}{-1.30102999566}

n = 2.84310893421

n = 3 (Approximated)

<em>Hence, the smallest number of servers required is 3 servers</em>

6 0
3 years ago
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