The longest possible integer length of the third side of the triangle is 6 < x < 28
The sum of any two sides must be greater than the third side for a triangle to exist
let the third side be x
x + 11 > 17 and x + 17 > 11 and 11 + 17 > x
x > 6 and x > - 6 and x < 28
The longest possible integer length of the third side of the triangle is 6 < x < 28
The length of the 3 sides of a triangle needs to always be among (however no longer the same) the sum and the difference of the opposite two sides. As an example, take the instance of two, 6, and seven. and. consequently, the third side period should be extra than 4 and less than 8.
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Answer:
=x^3 y^3-3x^3y^2+4x^2y^3+3
Step-by-step explanation:
Answer:
9x-10y
Step-by-step explanation:
9x+y-2y-9y(Multiply by 1)
Combine like terms
9x-10y
The correct answer is ASA.
If you look at the steps given in the proof, you will see that are are given two different angles that are congruent. You also have a side that is in between the two angles. Therefore, we have ASA.
