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3 years ago

In a rectangular park that measures 80 yards by 18 yards, a dog runs from one corner to the

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

6 0

Pythagoras
a^2 + b^2 = c^2
80^2 + 18^2 = Answer^2
Answer= The square root of 6724
= 82 yards

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Alisiya [41]

Answer:

2$ I think

Step-by-step explanation:

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3 years ago

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A girls hair is 23 inches long how long and grows about half an inch every month how long will her hair be in 2 years

jasenka [17]

Answer:

Step-by-step explanation:

1/2 multiplied by (12 multiplied by 2)

1/2 (24)

= 12 inches grown + 23 inches

= 35 inches long

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3 years ago

Which of these sets could represent the side lengths of a right triangle?

Jlenok [28]

Answer:

{6, 8, 10} is a set which represents the side length of a right triangle.

Step-by-step explanation:

In a right triangle:

$(Base)^{2} + (Perpendicular)^{2} = (Hypotenuse)^{2}$

Now, in the given triplets:

(a) {4, 8, 12}

Here, $(4)^{2} + (8)^{2} = 16 + 64 = 80\\\implies H = \sqrt{80} = 8.94$

So, third side of the triangle 8.94 ≠ 12

Hence, {4, 8, 12} is NOT a triplet.

(b) {6, 8, 10}

Here, $(6)^{2} + (8)^{2} = 36 + 64 = 100\\\implies H = \sqrt{100} = 10$

So, third side of the triangle 10

Hence, {6, 8, 10} is a triplet.

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So, third side of the triangle 10 ≠ 15

Hence, {6, 8, 15} is NOT a triplet.

(d) {5, 7, 13}

Here, $(5)^{2} + (7)^{2} = 25 + 49 = 74\\\implies H = \sqrt{74} = 8.60$

So, third side of the triangle 8.60 ≠ 13

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3 years ago

What are the domain and range of f(x) = (1/6)x + 2?

Black_prince [1.1K]

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There is no restriction upon the values of x, or the values of y.

So the domain and range are both the set of all real numbers.

x=(-oo, +oo) and y=(-oo, +oo)

This can be further seen by the fact that this is a line with a slope of 1/6. So there is no restriction upon x as all values of x produce real values of y. And y approaches -oo as x approaches -oo and y approaches +oo as x approaches +oo.

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3 years ago

Kristen has 3/4

Snezhnost [94]

Answer:

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Step-by-step explanation:

Each doll's hair ribbon will be 0.083 (yards)

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3 years ago