The function of h is defined by hx=2x-7 what is the value of h8

anastassius [24]

X rays=E
Microwaves=A
Gamma rays=C
Radio waves=F
Infrared waves=D
Ultraviolet waves=B

8 0

2 years ago

A ball is shot upward from a slingshot at a velocity of 15 m/s the height of the ball after t seconds is given by h(t)=10+ 5t+1/

otez555 [7]

Answer:

The instantaneous velocity after eight seconds is 9 m/s

Step-by-step explanation:

Given as :

The ball shot upward with velocity of 15 m/s

The height of the ball after t sec is given as h(t) = $10 + 5t + \frac{1}{4}t^{2}$

Now, The instantaneous velocity after 8 sec = $\frac{\partial h(t)}{\partial t}$

Or, The instantaneous velocity = $\frac{\partial (10 +5t + \frac{1}{4}t^{2})}{\partial t}$

or, The instantaneous velocity = $5 + \frac{1}{4}\times 2 t$

Now at t = 8 sec

The instantaneous velocity = 5 + 4 = 9 m/s

Hence The instantaneous velocity of ball at t = 8 sec , is 9 m/s Answer

3 0

3 years ago

Please answer it would help me a lot

Deffense [45]

Find if all the ratios are proportional to 1:8. 2:16 is, so is 3:24, and 4:32. 4.5*8=36, and 5:40 is proportional. 6:48 is, and 6.5*8=52. The table is proportional, just divide the pay by the hours and you should be getting 8.

5 0

3 years ago

The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of

defon

The abscissa of the ordered pair, that is the x-coordinate, is equal to 1 and the ordinate, the y-coordinate, is equal to -1. In the cartesian plane, this point lies in the fourth (IV) quadrant. The standard position of the angle is that which has one of its side is in the x-axis.

Solve for the hypotenuse of the right triangle formed.
h = sqrt((-1)² + (1)²) = √2
Below items show the calculation for each of the trigonometric functions.

sin θ = opposite/hypotenuse = y/h = (-1)/(√2) = -√2/2
cos θ = adjacent/hypotenuse = x/h = (1)/√2 = √2/2
tan θ = opposite/adjacent = y/x = -1/1 = -1

7 0

3 years ago

Graph the hyperbola using the transverse axis, vertices, and co-vertices:

Reptile [31]

See attachment for the graph of the hyperbola 12x^2 - 3y^2 - 108 = 0

<h3>How to graph the hyperbola?</h3>

The equation of the hyperbola is given as:

12x^2 - 3y^2 - 108 = 0

Start by calculating the transverse axis

So, we have:

<u>Transverse axis</u>

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

Where

a = 3 and b = 6

The transverse axis is calculated as:

y = ±b/a(x - h) + k

So, we have:

y = ±6/3(x - 0) + 0

Evaluate the difference and sum

y = ±6/3x

Evaluate the quotient

y = ±2x

This means that the transverse axes are y = 2x and y =-2x

<u>The vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

<u>The co-vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

And

a = 3 and b = 6

The co-vertices are

(h - a, k) and (h + a, k)

So, we have:

(0 - 3, 0) and (0 + 3, 0)

Evaluate

(-3,0) and (3, 0)

See attachment for the graph of the hyperbola