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Neko [114]
3 years ago
14

If the average grade on an English class rose from 70 to 85 what is the approximate percent increase ?

Mathematics
2 answers:
Whitepunk [10]3 years ago
8 0

Answer:21%!

Step-by-step explanation:

mixer [17]3 years ago
4 0

Answer: The approximate percent increase is 121.42857%. This is a rounded value. To get this, first you would need to find out which increased and in what direction. Of course, the 70 turned into an 85. So you can divide 85 by 70 and receive a number. Then in whatever form you found it, decimal, fraction, or even percent straight away, ensure the value is a percentage.

70 -> 85

85/70

About 1.21 [decimal]

1.21 x 100 = 121 [add the %]

121% [rounded]


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In a game, 3 people are chosen in the first round. Each of those people chooses 3 people in the second round and so on. How many
tatiyna

Answer:

729 people chosen

Step-by-step explanation:

4 calculations in head when 3^2 = 9

3 calculations in head when 3^3 = 27

2 calculations in head when 3^4 = 81

1 calculations in head when 3^5 = 243

Answer found 3^6 = 729.

3  = 1st       = 3^1

9  = 2nd    = 3^2         3(3)

27  = 3rd   = 3^3         9(3)

81  = 4th    = 3^4        27(3)

243 = 5th  = 3^5       81(3)

729 = 6th = 3^6        243(3)

4 0
2 years ago
Given f(x)= 2x^3+kx-1, and x+1 is a factor of f(x), then what is the value of k?
VMariaS [17]

Answer:

put x=-1, and the rest will be easy

5 0
2 years ago
Read 2 more answers
Don't comment. Don't even dare to press to ch.at. Just dont.
sergij07 [2.7K]

thanks for the points dude

4 0
2 years ago
Will mark brainliest and 15 points
insens350 [35]

Answer:

Step-by-step explanation:

x - 3y  -15

x = -3

6 0
2 years ago
Find the directional derivative of the function at the given point in the direction of the vector v. f(x, y, z) = xyz , (3, 3, 9
Anna [14]

The derivative of f(x,y,z) in the direction of a vector \mathbf u is

\nabla_{\mathbf u}f=\nabla f\cdot\dfrac{\mathbf u}{\|\mathbf u\|}

With f(x,y,z)=xyz, we get

\nabla f=(yz,xz,xy)

and \mathbf u=(-1,-2,2),

\|\mathbf u\|=\sqrt{(-1)^2+(-2)^2+2^2}=3

Then

\nabla_{(-1,-2,2)}f(3,3,9)=(27,27,9)\cdot\dfrac{(-1,-2,2)}3=-21

8 0
3 years ago
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