Answer:
c a b
Step-by-step explanation:
brailiest pls
Answer:
about 53 :)
Step-by-step explanation:
800 divided by 15
Answer:
(-10,-7)=x1,y1
m=10/3
we have,
y-y1=m(x-x1)
y+7=10/3(x+10)
3y+21=10x+100
y=10/3x+79/3
so the value of b is 79/3
The "standard" parabola with roots 0 and 2 is
![y = (x-0)(x-2) = x^2-2x](https://tex.z-dn.net/?f=y%20%3D%20%28x-0%29%28x-2%29%20%3D%20x%5E2-2x)
All multiples of this parabola, i.e.
![y=a(x^2-2x)](https://tex.z-dn.net/?f=y%3Da%28x%5E2-2x%29)
have the same roots. We can choose the factor such that the parabola passes through the desided point: if we plug 1, 5 for x, y we have
![5 = a(1-2) \iff -a=5 \iff a=-5](https://tex.z-dn.net/?f=5%20%3D%20a%281-2%29%20%5Ciff%20-a%3D5%20%5Ciff%20a%3D-5)
So, our claim is that the parabola
![y=-5(x^2-2x) = -5x^2+10x](https://tex.z-dn.net/?f=y%3D-5%28x%5E2-2x%29%20%3D%20-5x%5E2%2B10x)
has roots 0 and 2 and vertex at (1, 5).
You can easily verify this: the roots are guaranteed by the fact that we can write the equation as
![y = -5x(x-2)](https://tex.z-dn.net/?f=y%20%3D%20-5x%28x-2%29)
The vertex must be at x=1, because it's the midpoint of the roots. Moreover, if we evaluate the function at x=1 we have
![y(1) = -5\cdot 1 \cdot (1-2) = -5 \cdot 1 \cdot (-1) = 5](https://tex.z-dn.net/?f=y%281%29%20%3D%20-5%5Ccdot%201%20%5Ccdot%20%281-2%29%20%3D%20-5%20%5Ccdot%201%20%5Ccdot%20%28-1%29%20%3D%205)
as required.
Answer:
x <6
Step-by-step explanation:
5x-9 < 21
Add 9 to each side
5x-9+9 < 21+9
5x< 30
Divide each side by 5
5x/5 <30/5
x <6