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Damm [24]
3 years ago
6

Complete the equation of the graphed linear function. Write the slope in decimal form. y = x The graph of the function goes thro

ugh point negative 5, 0 and point 0, 4.
Mathematics
1 answer:
docker41 [41]3 years ago
4 0
The slope is .8. I don't know what that is in a fraction. the equation is y=.8x+4

0-4= -4
-5-0=-5 -4/-5= .8

y-4=.8(x-0)

y-4=.8x
+4    +4
y=.8x+4

I hope this helps. That is generally what i di to solve the equation.
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4 0
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Assuming x &gt; 0, which of these expressions is equivalent to 11 times the square root of 245 x to the third plus 9 times the s
ehidna [41]
The answer is <span>104 x times the square root of 5 x 
</span>
<span>11 times the square root of 245 x to the third plus 9 times the square root of 45 x to the third is:
</span>11 \sqrt{245 x^{3} } +9 \sqrt{45 x^{3} } =11 \sqrt{245}  *\sqrt{ x^{3} } +9 \sqrt{45} *\sqrt{ x^{3} }= \\  \\ =11 \sqrt{5*49} * \sqrt{ x^{2} *x} +9 \sqrt{5*9} * \sqrt{ x^{2} *x}= \\  \\ =11* \sqrt{5}  * \sqrt{49} * \sqrt{ x^{2}} * \sqrt{x} +9* \sqrt{5} * \sqrt{9} * \sqrt{ x^{2} }* \sqrt{x} = \\  \\ &#10;=11* \sqrt{5} *7*x* \sqrt{x} +9* \sqrt{5} *3*x* \sqrt{x} = \\  \\ &#10;=77x* \sqrt{5*x} +27x* \sqrt{5*x}  = \\  \\ &#10;=77x \sqrt{5x} +27x \sqrt{5x} = \\  \\ &#10;=104x \sqrt{5x}
4 0
3 years ago
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