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AleksAgata [21]
3 years ago
15

The points obtained by students of a class in a test are normally distributed with a mean of 60 points and a standard deviation

of 5 points.
About what percent of students have scored between 60 and 65 points?
Mathematics
1 answer:
dolphi86 [110]3 years ago
6 0

Answer:

Step-by-step explanation:

This fraction represents the area under the standard normal curve between 60 and 65 points.  This represents the area from the mean (60) to one standard deviation above the mean (65).  The applicable z-score is

       65 - 60

z = --------------- = 1.

             5

The problem then involves finding the area under the curve from z = 0 (that is, the mean) to z = 1 (one standard deviation above the mean).

Refer to the "empirical rule."  This rule states that 68% of data lies within one standard deviation of the mean, that is, within z = -1 and z = 1.  We are interested only in the area that is within z = 0 and z = 1, which is half of 68%, and thus is 34%.

In summary, approx. 34% of students have scored between 60 and 65 points.

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Answer:

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According to the graph, the line goes down in both sections as the value of x increases. It means the function is always decreasing.

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If you multiply the radius of a sphere by 'anything',
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Going the other direction, if you multiply the volume by
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In this question, the ratio of the volumes is  3 .
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3 years ago
The sum of -7 times a number and 8 times the sum of the number and 1 is the same as the number minus 7
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Answer:

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Step-by-step explanation:

The number will be represented by x

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Add like terms

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Answer:

The standard deviation of the age distribution is 6.2899 years.

Step-by-step explanation:

The formula to compute the standard deviation is:

SD=\sqrt{\frac{1}{n}\sum\limits^{n}_{i=1}{(x_{i}-\bar x)^{2}}}

The data provided is:

X = {19, 19, 21, 25, 25, 28, 29, 30, 31, 32, 40}

Compute the mean of the data as follows:

\bar x=\frac{1}{n}\sum\limits^{n}_{i=1}{x_{i}}

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Compute the standard deviation as follows:

SD=\sqrt{\frac{1}{n}\sum\limits^{n}_{i=1}{(x_{i}-\bar x)^{2}}}

      =\sqrt{\frac{1}{11-1}\times [(19-27.182)^{2}+(19-27.182)^{2}+...+(40-27.182)^{2}]}}\\\\=\sqrt{\frac{395.6364}{10}}\\\\=6.28996\\\\\approx 6.2899

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