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a_sh-v [17]
3 years ago
9

(3f–3)^2 pls help aaaaaaaaaaaaaaaaaaaa

Mathematics
1 answer:
julia-pushkina [17]3 years ago
6 0
9f^2-18f+9 is the answer
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A computer costs £927 plus VAT, where VAT is charged 20% find the total cost of the computer
liubo4ka [24]

A computer costs 927 plus VAT where VAT is 20%. We need to find the total cost of the computer.

The total cost = original cost + VAT

Total Cost = 927 + 20% * 927

20% converts to decimal by moving the decimal 2 units up, so it is 0.2

= 927 + 0.2*927

Multiply to find value of tax

= 927 + 185.4

Add to find the total cost

Total cost = 1112.4 euros

8 0
3 years ago
When a coin is tossed it is either heads or tails. Suppose heads has a point value of 1 and tails a point value of -1. if the su
zvonat [6]

Answer:

32

Step-by-step explanation:

Totally there are 50 tosses.  

Let the number of tosses which resulted head be x.  

Therefore the number of tosses which resulted tail is 50−x.

We get x×1+(50−x)×(−1)=14

x−(50−x)=14

x−50+x=14

x=32

8 0
3 years ago
Given the directrix of y = 6 and focus of (0, 4), which is the equation of the parabola?\
Yuliya22 [10]

Answer:

The directrix is y=6 and focus is (0,4)

The equation of the parabola is,

20-4y=x²

5 0
3 years ago
Find the area of a rectangle that length is 7n^2 +3n and width 2n^3
WITCHER [35]

Answer:a

Step-by-step explanation: avnvgjv

A

4 0
3 years ago
Suppose you solved a second-order equation by rewriting it as a system and found two scalar solutions: y = e^5x and z = e^2x. Th
xenn [34]

Answer:

The solutions are linearly independent because the Wronskian is not equal to 0 for all x.

The value of the Wronskian is \bold{W=-3e^{7x}}

Step-by-step explanation:

We can calculate the Wronskian using the fundamental solutions that we are provided and their corresponding the derivatives, since the Wroskian is defined as the following determinant.

W = \left|\begin{array}{cc}y&z\\y'&z'\end{array}\right|

Thus replacing the functions of the exercise we get:

W = \left|\begin{array}{cc}e^{5x}&e^{2x}\\5e^{5x}&2e^{2x}\end{array}\right|

Working with the determinant we get

W = 2e^{7x}-5e^{7x}\\W=-3e^{7x}

Thus we have found that the Wronskian is not 0, so the solutions are linearly independent.

3 0
3 years ago
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