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3 years ago

In this picture what is the value of x

Mathematics

2 answers:

zlopas [31]3 years ago

8 0

Add the 75 and 79 which gives u 154
then subtract it by 180 and should give you 26 as your final answer

Anvisha [2.4K]3 years ago

8 0

Hey There,

Initially, you would add the angle already provided.

75 + 79= 154

Now you would subtract 154 from 180.

180 - 154= 26

Therefore, the answer would be A) 26.

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Explain why 3/4 and 9/12 are equivalent?

Nikitich [7]

They’re equivalent because 3 • 3 is 9 and whatever you do to the top, you do to the bottom, therefore 4 • 3 is 12. That would equal 9/12.

8 0

4 years ago

Read 2 more answers

Bob has 10 dollars. His parents took away 5 dollars because he did not do his chores. Then he got 25 more dollars from a friend.

Sauron [17]

Answer:

$30

Step-by-step explanation:

He first has 10 dollars. Then 5 is taken off.

So, 10-5=5

His friend gives him 25 more dollars

So, 25+5= 30

Hope this helped!

4 0

4 years ago

. Given ????(5, −4) and T(−8,12):

damaskus [11]

Answer:

a) $y=\dfrac{13x}{16}-\dfrac{129}{16}$

b) $y = \dfrac{13x}{16}+ \dfrac{37}{2}$

Step-by-step explanation:

Given two points: $S(5,-4)$ and $T(-8,12)$

Since in both questions,a and b, we're asked to find lines that are perpendicular to ST. So, we'll do that first!

Perpendicular to ST:

the equation of any line is given by: $y = mx + c$ where, m is the slope(also known as gradient), and c is the y-intercept.

to find the perpendicular of ST <u>we first need to find the gradient of ST, using the gradient formula.</u>

$m = \dfrac{y_2 - y_1}{x_2 - x_1}$

the coordinates of S and T can be used here. (it doesn't matter if you choose them in any order: S can be either x_1 and y_1 or x_2 and y_2)

$m = \dfrac{12 - (-4)}{(-8) - 5}$

$m = \dfrac{-16}{13}$

to find the perpendicular of this gradient: we'll use:

$m_1m_2=-1$

both $m_1$ and $m_2$ denote slopes that are perpendicular to each other. So if $m_1 = \dfrac{12 - (-4)}{(-8) - 5}$ , then we can solve for $m_2$ for the slop of ther perpendicular!

$\left(\dfrac{-16}{13}\right)m_2=-1$

$m_2=\dfrac{13}{16}$ :: this is the slope of the perpendicular

a) Line through S and Perpendicular to ST

to find any equation of the line all we need is the slope $m$ and the points $(x,y)$ . And plug into the equation: $(y - y_1) = m(x-x_1)$

side note: you can also use the $y = mx + c$ to find the equation of the line. both of these equations are the same. but I prefer (and also recommend) to use the former equation since the value of 'c' comes out on its own.

$(y - y_1) = m(x-x_1)$

we have the slope of the perpendicular to ST i.e $m=\dfrac{13}{16}$