Answer:
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Step-by-step explanation:
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Answer:β=√10 or 3.16 (rounded to 2 decimal places)
Step-by-step explanation:
To find the value of β :
- we will differentiate the y(x) equation twice to get a second order differential equation.
- We compare our second order differential equation with the Second order differential equation specified in the problem to get the value of β
y(x)=c1cosβx+c2sinβx
we use the derivative of a sum rule to differentiate since we have an addition sign in our equation.
Also when differentiating Cosβx and Sinβx we should note that this involves function of a function. so we will differentiate βx in each case and multiply with the differential of c1cosx and c2sinx respectively.
lastly the differential of sinx= cosx and for cosx = -sinx.
Knowing all these we can proceed to solving the problem.
y=c1cosβx+c2sinβx
y'= β×c1×-sinβx+β×c2×cosβx
y'=-c1βsinβx+c2βcosβx
y''=β×-c1β×cosβx + (β×c2β×-sinβx)
y''= -c1β²cosβx -c2β²sinβx
factorize -β²
y''= -β²(c1cosβx +c2sinβx)
y(x)=c1cosβx+c2sinβx
therefore y'' = -β²y
y''+β²y=0
now we compare this with the second order D.E provided in the question
y''+10y=0
this means that β²y=10y
β²=10
B=√10 or 3.16(2 d.p)
Answer:
31
Step-by-step explanation:
A=2(wl+hl+hw)
l -Length
w-Width
h-Height
A=2(wl+hl+hw)=2·(1·2+4.5·2+4.5·1)=31
The domain of a function refers to the interval of x values where the graph is defined. In order for the function to be at least 600, the x values must be between 0 and 20.
The answer is:
Answer:
IJ = 34
Step-by-step explanation:
Since HK = JK, then IK is a perpendicular bisector and Δ is isosceles, then
IJ = HI , that is
2s = s + 17 ( subtract s from both sides )
s = 17
Then
IJ = 2s = 2 × 17 = 34
