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Nataliya [291]
3 years ago
6

Find two numbers if their ratio is 4:7 and their difference is 123. help

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
7 0

Answer:

The numbers are 164  and  287

Step-by-step explanation:

Let

x-------> the first number

y-----> the second number

we know that

\frac{x}{y}=\frac{4}{7}

x=\frac{4}{7}y -----> equation A

y-x=123 -----> equation B

substitute equation A in equation B

y-\frac{4}{7}y=123

\frac{3}{7}y=123

y=123*7/3=287

Find the value of x

x=\frac{4}{7}(287)=164

Karo-lina-s [1.5K]3 years ago
5 0

Answer:

  164 and 287

Step-by-step explanation:

Their difference is 7-4 = 3 ratio units, so each ratio unit must stand for 123/3 = 41.

Then the numbers are 4·41 and 7·41, or 164 and 287.

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How does the graph of the function g(x) = 2x – 4 differ from the graph of f(x) = 2x
Lena [83]

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Answer:

  the y-intercepts differ

Step-by-step explanation:

The x-coefficient is the same for each function, so parallel lines are described. The function g(x) has a y-intercept of -4; f(x) has a y-intercept of 0.

The graphs differ in their intercepts.

__

<em>Additional comment</em>

g(x) can be considered to be a translation downward of f(x) by 4 units. The same graph of g(x) can be obtained by translating f(x) to the right by 2 units. That is, both the x-intercepts and y-intercepts differ between the two functions.

5 0
3 years ago
9 - 12n 2 + 4n 3 - 7n
Naddika [18.5K]
1) is the correct answer because you just have to arrange them by degree
3 0
3 years ago
Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule
Sergeeva-Olga [200]

Answer:

First term: 5

Fourth term: 5 1/2

Tenth term: 6 1/2

Step-by-step explanation:

Let's find the first, fourth and tenth terms of the arithmetic sequence described by the given rule:

A(n) = 5 + (n-1) (1/6)

First term:

A(1) = 5 + (1-1) (1/6)

A(1) = 5 + (0) (1/6)

A(1) = 5

Fourth term:

A(4) = 5 + (4-1) (1/6)

A(4) = 5 + (3) (1/6)

A(4) = 5 + 3/6 = 5 3/6 = 5 1/2 (simplifying)

Tenth term:

A(10) = 5 + (10-1) (1/6)

A(10) = 5 + (9) (1/6)

A (10) = 5 + 9/6 = 6 3/6 = 6 1/2 (simplifying)

5 0
4 years ago
A. x ≥ 0
AlladinOne [14]

Answer:

D

Step-by-step explanation:

8 0
3 years ago
Craig ran the first part of a race with an average speed of 8 miles per hour and biked the second part of a race with an average
lutik1710 [3]
Let the distance of the first part of the race be x, and that of the second part, 15 - x, then
x/8 + (15 - x)/20 = 1.125
5x + 2(15 - x) = 40 x 1.125
5x + 30 - 2x = 45
3x = 45 - 30 = 15
x = 15/3 = 5

Therefore, the distance of the first part of the race is 5 miles and the time is 5/8 = 0.625 hours or 37.5 minutes
The distance of the second part of the race is 15 - 5 = 10 miles and the time is 1.125 - 0.625 = 0.5 hours or 30 minutes.
4 0
3 years ago
Read 2 more answers
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