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3 years ago

How many 2/3s does it take to make 10/3

Mathematics

1 answer:

soldi70 [24.7K]3 years ago

3 0

Answer:

5 2/3's

Step-by-step explanation:

You might be interested in

How can you find f(2) if f(x) = 3x2 – 2?

Olegator [25]

Answer:

Step-by-step explanation:

Plug in 2 for x.

f(2) = 3·(2)²-2

=3·4-2

=12-2

=10

8 0

2 years ago

Read 2 more answers

Goran and karen walk around a track . goran walks each lap in 10 minutes. karen walks each lap in 6 minutes. they both start at

Nimfa-mama [501]

Goran completes 6. karen completes 10. it takes 60 minutes

7 0

3 years ago

Combine like terms: 3p2q2-3p2q3+4p2q3-3p2q2+pq PLEASE HELP!!! ASAP!!!

ch4aika [34]

Answer:

p²q³ + pq and pq(pq² + 1)

Step-by-step explanation:

Given

3p²q² - 3p²q³ +4p²q³ -3p²q² + pq

Required

Collect like terms

We start by rewriting the expression

3p²q² - 3p²q³ +4p²q³ -3p²q² + pq

Collect like terms

3p²q² -3p²q² - 3p²q³ +4p²q³ + pq

Group like terms

(3p²q² -3p²q²) - (3p²q³ - 4p²q³ ) + pq

Perform arithmetic operations on like terms

(0) - (-p²q³) + pq

- (-p²q³) + pq

Open bracket

p²q³ + pq

The answer can be further simplified

Factorize p²q³ + pq

pq(pq² + 1)

Hence, 3p²q² - 3p²q³ +4p²q³ -3p²q² + pq is equivalent to p²q³ + pq and pq(pq² + 1)

7 0

3 years ago

A flying squirrel lives in a nest that is 9 meters high in a tree. To reach a fallen acorn that is 4 meters from the base of the

Luba_88 [7]

Answer:

Flying squirrel have to glide is for 9.8 meters approximately.

Step-by-step explanation:

Here we can use Pythagoras theorem.

Height is 9 , base is 4.

We need to find the hypotenuse measure.

So, let's use Pythagoras theorem $a^{2} +b^{2}= c^{2}$

Plug in a as 9 and b 4.

$9^{2} +4^{2}=c^{2}$

Simplify the left side of the equation

$81+16=c^{2}$

$97=c^{2}$

Take square root on both sides.

c=9.8 meters.

6 0

2 years ago

What is the area of a triangle with vertices (3,0) (9,0) (7,6)

Nezavi [6.7K]

Answer:

The area of the triangle is of 21 units of area.

Step-by-step explanation:

The area of a triangle with three vertices $(x_1,y_1),(x_2,y_2),(x_3,y_3)$ is given by the determinant of the following matrix:

$A = \pm 0.5 \left|\begin{array}{ccc}x_1&y_1&1\\x_2&y_2&1\\1_3&y_3&1\end{array}\right|$

In this question:

Vertices (3,0) (9,0) (7,6). So

$A = \pm 0.5 \left|\begin{array}{ccc}3&0&1\\9&0&1\\7&7&1\end{array}\right|$

$A = \pm 0.5(3*0*1+0*1*7+1*9*7-0*7*1-0*9*1-3*1*7)$

$A = \pm 0.5*(63-21)$

$A = \pm 0.5*42 = 21$

The area of the triangle is of 21 units of area.

5 0

2 years ago